Implement sorting algorithm using JS
This time I will bring you the use of JS to implement the sorting algorithm and the use of JS to implement the sorting algorithm. Notes What are the following? Let’s take a look at the actual cases.
Some common js sorting algorithm implementations, non-original, used for recording
Time complexity: O(n^2) ;
Fastest: when the data is in positive sequence
Slowest: when the data is in reverse sequence
function bubbleSort(arr) { var len = arr.length; for (var i = 0; i < len; i++) { for (var j = 0; j < len - 1 - i; i++) { // 相邻元素两两对比，元素交换
if (arr[j] > arr[j + 1]) { var temp = arr[j + 1];
arr[j + 1] = arr[j];
arr[j] = temp;
}
}
} return arr;
}Time complexity: O(n ^2)
The most stable sorting algorithm
function selectionSort(arr) { var len = arr.length; var minIndex, temp; // 寻找最小的数，将索引保存
for (var i = 0; i < len - 1; i++) {
minIndex = i; for (var j = i + 1; j < len; j++) { if (arr[j] < arr[minIndex]) {
minIndex = j;
}
}
temp = arr[i];
arr[i] = arr[minIndex];
arr[minIndex] = temp;
} return arr;
}Insertion sort
Time complexity: O(n^2);
Poker sort
function insertionSort(arr) { var len = arr.length; var preIndex, current; for (var i = 1; i < len; i++) {
preIndex = i - 1;
current = arr[i]; while (preIndex >= 0 && arr[preIndex] > current) {
arr[preIndex + 1] = arr[preIndex];
preIndex--;
}
arr[preIndex + 1] = current;
} return arr;
}Hill Sorting
Time complexity: O(n log n);
function shellSort(arr) { var len = arr.length, temp, gap = 1; //动态定义间隔序列
while (gap < len / 3) {
gap = gap * 3 + 1;
} for (gap; gap > 0; gap = Math.floor(gap / 3)) { for (var i = gap; i < len; i++) {
temp = arr[i]; for (var j = i - gap; j >= 0 && arr[j] > temp; j -= gap) {
arr[j + gap] = arr[j];
}
arr[j + gap] = temp;
}
} return arr;
}Merge sort
Time complexity: O(n log n);
function mergeSort(arr) { var len = arr.length; if (len < 2) { return arr;
} var middle = Math.floor(len / 2),
left = arr.slice(0, middle),
right = arr.slice(middle); return merge(mergeSort(left), mergeSort(right)); function merge(left, right) { var result = []; while (left.length && right.length) { if (left[0] <= right[0]) {
result.push(left.shift());
} else {
result.push(right.shift());
}
} while (left.length)
result.push(left.shift()); while (right.length)
result.push(right.shift()); return result;
}
}I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!
Recommended reading:
Strategy Pattern of Javascript
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