Home Web Front-end JS Tutorial Simple implementation of Ajax uploading pictures and previewing them

Simple implementation of Ajax uploading pictures and previewing them

May 23, 2018 pm 02:30 PM
ajax Simple Preview

Below I will bring you a simple implementation of Ajax uploading pictures and previewing them. Let me share it with you now and give it as a reference for everyone.

1. Go directly to the simplest ajax asynchronous upload image and preview

html:

<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>图片上传 | cookie</title>
</head>
<body>
  file: <input type="file" id="images" name="image" /><br><br>
  desc: <input type="text" id="desc" name="desc" /><br><br>
  <input type="button" value="upload" onclick="upload();">
  
  <p class="images"></p>
  
<script type="text/javascript" src="js/jquery-1.12.4.min.js"></script>
<script type="text/javascript" src="js/upload.js"></script>
<script type="text/javascript">
  function upload() {
    $.ajaxFileUpload({
      url : &#39;upload.htm&#39;,
      fileElementId : &#39;images&#39;,
      dataType : &#39;json&#39;,
      data : {desc : $("#desc").val()},
      success : function(data) {
        var html = $(".images").html();
        html += &#39;<img width="100" height="100" src="/HotelManager/upload/&#39; + data.url + &#39;">&#39;
        $(".images").html(html);
      }
    })
    return false;
  }
</script>
</body>
</html>
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servlet:

protected void doPost(HttpServletRequest request, HttpServletResponse response)
      throws ServletException, IOException {
    DiskFileItemFactory factory = new DiskFileItemFactory();
    
    ServletFileUpload upload = new ServletFileUpload(factory);
    
    String path = request.getServletContext().getRealPath("/upload");
    String name = null;
    try {
      List<FileItem> items = upload.parseRequest(request);
      for (FileItem item : items) {
        if(item.isFormField()){
          System.out.println(item.getFieldName() + ": " + item.getString());
        } else {
          name = item.getName();
          item.write(new File(path,name));
        }
      }
      PrintWriter out = response.getWriter();
      out.print("{");
      out.print("url:\"" + name +"\"");
      out.print("}");
      
    } catch (Exception e) {
      e.printStackTrace();
    }
  }
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The above is what I compiled for everyone. I hope it will be helpful to everyone in the future.

Related articles:

Summary of file upload skills based on ajax html

A simple example of using XPath in dom4j

A brief discussion on Bootstrap’s DatePicker date range selection

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