Home Web Front-end Front-end Q&A jquery ajax form submission does not refresh the page

jquery ajax form submission does not refresh the page

May 18, 2023 pm 08:19 PM

In web development, form submission is a very common operation, and usually, form submission is completed by refreshing the page. However, what if you don’t want to refresh the page after submitting the form? This article will introduce how to use jQuery and Ajax to implement form submission without refreshing the page.

1. Why not refresh the page

In the traditional form submission process, users must wait patiently for the page to refresh, which will make the user experience very cumbersome. If the page is refreshed, the user may need to re-enter the previously filled form content, which will make the user unhappy. In addition, page refresh may also cause the loss of some data, which will also cause unnecessary trouble to users.

Therefore, implementing form submission without refreshing the page through Ajax can effectively improve the user experience and save users' time and energy.

2. Implementation steps

Below, we will use the following steps to implement form submission without refreshing the page.

  1. Listen to the form submission event

First, we need to bind a listener function for the submit event on the form, so that the form can be submitted through JavaScript. At the same time, we need to prevent the browser's default form submission behavior by returning false. The code is as follows:

$('form').submit(function() { 
  // ajax 表单提交代码... 
  return false; 
}); 
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  1. Get form data

Next, we need to get the form data through jQuery’s serialize() method. This method serializes all data in the form into a string for use in subsequent Ajax requests. The code is as follows:

var formData = $('form').serialize(); 
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  1. Send Ajax request

Now, we need to send an asynchronous request through jQuery's ajax() method to submit the form without refreshing the page. The code is as follows:

$.ajax({ 
  type: 'POST', 
  url: 'submit.php', 
  data: formData, 
  success: function(result) { 
    // 处理返回的数据 
  } 
}); 
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In this ajax() method, we define the following parameters:

  • type: The type of request. In this example, we chose the POST method.
  • url: The requested target URL. Here is submit.php, which represents the PHP file that will send the data after the form is submitted.
  • data: Data sent to the server. We used the form data obtained previously, formData.
  • success: The callback function after the request is successful. In this function, we can process the data returned by the server accordingly.
  1. Processing the data returned by the server

When the server returns the data, we can process it in the success callback function. For example, we can display the data returned by the server on the page, or change the status of the page through JavaScript. The code is as follows:

success: function(result) { 
  // 处理返回的数据: 
  alert(result); 
  $('form')[0].reset(); 
} 
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In this callback function, we perform two operations on the data returned by the server:

  • Display a prompt box through the JavaScript alert() method, The content is the data returned by the server.
  • The form is reset through jQuery's reset() method so that users can fill in new data.

So far, through the above four steps, we have successfully implemented form submission without refreshing the page.

3. Notes

Although form submission through Ajax can greatly improve the user experience, there are also some things that need to be paid attention to during use:

  1. Prevent repeated submission of forms

Because Ajax requests are asynchronous, when users frequently click the submit button, the form may be submitted repeatedly. To avoid this problem, we can disable the form's submit button while sending the Ajax request and enable it after the request is completed. The code is as follows:

$('form').submit(function() { 
  // 禁用按钮 
  $('input[type="submit"]', this).attr('disabled', 'disabled'); 

  // ajax 表单提交代码... 

  // 启用按钮 
  $('input[type="submit"]', this).removeAttr('disabled'); 
}); 
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  1. Handling errors returned by the server

In Ajax requests, if the server returns an incorrect status code, we need to handle these errors in a timely manner . Normally, we can judge the status returned by the server through the data in the success callback function, and perform subsequent processing according to the specific situation. For example, when the status code returned by the server is 401, it may mean that the user is not logged in. In this case, we need to log in the user through a page jump to continue accessing.

success: function(result) { 
  if (result.status === 'success') { 
    alert('提交成功'); 
    $('form')[0].reset(); 
  } else if (result.status === 'failed') { 
    alert('提交失败'); 
  } else if (result.status === 'error') { 
    alert('发生了错误:' + result.message); 
  } 
} 
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4. Summary

This article introduces how to use jQuery and Ajax to achieve form submission without refreshing the page. By listening to the form submission event, obtaining the form data, sending an Ajax request and processing the data returned by the server, we can implement a form submission without refreshing the page and greatly improve the user experience. Of course, you also need to pay attention to some potential problems when using it, such as preventing repeated submission of forms and handling errors returned by the server. I hope this article will help you implement form submission without refreshing the page.

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