Table of Contents
Differences and solutions for JSONObject and Map serialization
Problem description
Problem analysis
Solution
Home Java javaTutorial What is the reason why the results of JSONObject and Map serialization are inconsistent? How to solve it?

What is the reason why the results of JSONObject and Map serialization are inconsistent? How to solve it?

Apr 19, 2025 pm 10:21 PM
Solution key value pair

What is the reason why the results of JSONObject and Map serialization are inconsistent? How to solve it?

Differences and solutions for JSONObject and Map serialization

In Java, when using different data structures (such as net.sf.json.JSONObject and java.util.Map ) for JSON serialization, there may be inconsistent results. This article analyzes this problem and provides solutions.

Problem description

The following code snippet shows the process of using JSONObject and Map to process data containing type fields and serialize using ObjectMapper :

 @Test
public void testSerialization() throws JsonProcessingException {
    ObjectMapper objectMapper = new ObjectMapper();
    List<string> type = Arrays.asList("a", "b");

    JSONObject jsonObject = new JSONObject();
    jsonObject.put("type", objectMapper.writeValueAsString(type));
    System.out.println("JSONObject Result: " objectMapper.writeValueAsString(jsonObject));

    Map<string object> map = new HashMap();
    map.put("type", objectMapper.writeValueAsString(type));
    System.out.println("Map Result: " objectMapper.writeValueAsString(map));
}</string></string>
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The output may be as follows:

 <code>JSONObject Result: {"type":["a","b"]} Map Result: {"type":"[\"a\",\"b\"]"}</code>
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As you can see, the serialization result of JSONObject is ["a","b"] , while the serialization result of Map is "[\"a\",\"b\"]" . This stems from the different ways that ObjectMapper handles JSONObject and Map .

Problem analysis

net.sf.json.JSONObject is an older JSON library that may have problems with its compatibility with modern ObjectMapper (Jackson library). ObjectMapper may treat JSONObject as a special JSON object, while performing standard key-value pair serialization on Map . This leads to differences in serialization results. It is not best practice to use ObjectMapper directly for serializing JSONObject .

Solution

To avoid inconsistent serialization results, it is recommended to use more modern and powerful JSON libraries such as Jackson or Gson. Avoid mixing different JSON libraries. Here is the code rewritten with the Jackson library:

 @Test
public void testSerializationWithJackson() throws JsonProcessingException {
    ObjectMapper objectMapper = new ObjectMapper();
    List<string> type = Arrays.asList("a", "b");

    Map<string object> data = new HashMap();
    data.put("type", type); // Put it directly into List without quadratic serialization System.out.println("Jackson Result: " objectMapper.writeValueAsString(data));
}</string></string>
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This code directly places List<string></string> As the value of Map , ObjectMapper will automatically perform correct serialization, and the output result is:

 <code>Jackson Result: {"type":["a","b"]}</code>
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This approach eliminates inconsistencies and provides cleaner, easier to maintain code. It is recommended to migrate completely to modern JSON libraries like Jackson or Gson for better performance and consistency. Avoid using net.sf.json.JSONObject .

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