1、connec.php
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<?php
$db = [
'type' => 'mysql',
'host' => '127.0.0.1',
'dbname' => 'baoge',
'username' => 'root',
'password' => 'root'
];
$dsn = "{$db['type']}:host={$db['host']};dbname={$db['dbname']}";
$username = $db['username'];
$password = $db['password'];
try {
$pdo = new PDO($dsn, $username, $password);
} catch (PDOException $e) {
die('连接失败' . $e->getMessage());
}
?>点击 "运行实例" 按钮查看在线实例
2、login.php
<!doctype html> <html lang="en"> <head> <meta charset="UTF-8"> <title>用户登录</title> </head> <body> <h3>用户登录</h3> <!-- 只要地址，能访问到，就可以把表单提交过去 --> <!-- 账号密码，如果用get提交，是会被浏览器显示出来的。 --> <form action="dispatch.php?a=check" method="post"> <p> <label for="phone">手机号:</label> <input type="phone" name="phone" id="phone"> </p> <p> <label for="password">密码:</label> <input type="password" name="password" id="password"> </p> <p> <button>提交</button> </p> </form> </body> </html>
点击 "运行实例" 按钮查看在线实例
3 index.php
<?php
// 点击去登录、退出，用户自己触发。
// 登录成功、退出成功，返回首页是js触发的。
// 我们现在没有学习js，所以 做了按钮跳转
// echo time();
if( isset( $_COOKIE['user'] ) ){
echo '登录成功，用户昵称：' . $_COOKIE['user'];
echo '<br>';
echo '<a href="dispatch.php?a=out">退出</a>';
}else{
echo '<a href="dispatch.php?a=login">请登录</a>';
}
?>点击 "运行实例" 按钮查看在线实例
、
4 out.php
<?php
setcookie('user',null,time()-3600);
echo '已退出';
echo '<br>';
echo '<a href="dispatch.php">首页</a>';
?>点击 "运行实例" 按钮查看在线实例
5 dispatch.php
<?php
header("Content-Type: text/html;charset=utf-8");
require __DIR__ . '/connect.php';
$a = isset($_GET['a']) ? $_GET['a'] : 'index';
switch ($a) {
case 'login':
# code...
include __DIR__ . '/login.php';
break;
case 'check':
include __DIR__ . '/check.php';
break;
case 'out':
include __DIR__ . '/out.php';
break;
case 'index':
include __DIR__ . '/index.php';
break;
default:
# code...
break;
}
?>点击 "运行实例" 按钮查看在线实例
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