


How to get the parameter name of a function in php_PHP Tutorial
Question
How to get the parameter name of a function?
Solution
$test = 'this is a test';
$abc = 'aaaaaaaaa';
getit($test);
function getit($l){
// Get the name of $l here instead of the value
// When $test does parameter input, the string '$test' is displayed instead of the value of $test
// When $abc is used as parameter input, the string '$abc' is displayed instead of the value of $abc
}
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Reference answer
this. . Does this work?
Can't seem to get it.
Unless you read the file, use regular matching.
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Original post by wbsifan on 2009-1-4 10:46 [url=http://bbs.111cn.cn/redirect.php?goto=findpost&pid=814417&ptid=100342]Link tag [img]http://bbs. 111cn.cn/images/common/back.gif[/img][/url]
$test = 'this is a test';
$abc = 'aaaaaaaaa';
getit($test);
function getit($l){
// Get the name of $l here instead of the value
// When $test does parameter input, the string '$test' is displayed instead of the value of $test
// When $abc ...
What’s your application?
getit('aaa');
What should be displayed? [img]http://www.111cn.cn/bbs/images/smilies/default/03.gif[/img]
Reference answer
significance. [img]http://www.111cn.cn/bbs/images/smilies/default/lol.gif[/img]
Reference answer
Don’t think about this yet...
Help me figure out how to get the parameter name...
Reference answer
Studying
Reference answer
I don’t quite understand what you mean. There is a pass-by-reference-by-value and pointer-by-value approach in C++, which may be useful to you
Reference answer
function test($val) {
if (is_array($val)){
foreach($val as $value){
$arr[]=$value;
}
return $arr;
}else {
$val = &$val;
return $val;
}
}
$val = 1;
var_dump(test($val));
echo "
";
$arr = array(1,2,3);
print_r(test($arr));
?>
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I understand what you mean but I don’t know how to implement it. I have never thought about it before. Learn·~··
Reference answer
int(1)
Array ( [0] => 1 [1] => 2 [2] => 3 )
To get the string '$arr'...that is, the parameter name instead of the parameter value..

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