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Home Backend Development PHP Tutorial php代码关于变量转义的问题

php代码关于变量转义的问题

Jun 20, 2016 pm 12:46 PM

$('a.video', toolbar).click(function() {			_this.save_bookmark();			_this.hide_menu();			$(this).xn_menu($('.video', menu), 0, 5000);			setTimeout(function() {				$('.video input.url', menu).focus().select();			}, 100);		});		$('.video input.insert', menu).click(function() {			var url = $('.video input.url', menu).val();			var width = $('.video input.w', menu).val();			var height = $('.video input.h', menu).val();			_this.add_video(url, width, height);			return true;		});		$('.video input.close', menu).click(function() {			_this.hide_menu();			_this.load_bookmark(true);			return true;		});
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this.add_video = function(url, width, height) {		width = intval(width);		height = intval(height);		var s = "<br><br><center><script type=\"text/javascript\" src=\"jwplayer/jwplayer.js\"></script><div id=\"mediaplayer\"></div> <script type=\"text/javascript\">jwplayer('mediaplayer').setup({'flashplayer': 'jwplayer/jwplayer.flash.swf','image': 'http://7vzuer.com1.z0.glb.clouddn.com/t013d040a81b623566f.jpg', 'id': 'playerID', 'width': '100%', 'aspectratio':'10:6', 'title':'"+height+"', 'tracks':'"+width+"', 'file': '"+url+"' });</script><br><br></center>";		_this.paste(s);				$('div.video', _this.menu).hide();	};
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以上是两个变量 width 和 height 全部被变量转换成整型变量 了,我现在两个变量输出的都是0,文字和字母输入后都不显示应该是被转换的缘故,我想请朋友帮我改改这段代码,要求输出的两个变量 width 和 height 
width 是URL形式的 height可以是文字 字幕 和数字形式(总之是去掉转型这块,代码我删除了转型的那两句但是依然还是输出的数值是0不知道怎么改了)


回复讨论(解决方案)

有没有人在啊?????????在线等

也没个人出来救救人

fasdfasfasdf

你这个是js,不是php
而js转整形的方法是parseInt 而不是intval, intval是php的方法

所以你的代码是错的。

var width = $('.video input.w', menu).val();
var height = $('.video input.h', menu).val();

这两个变量先打印出来看看是什么,估计这里就已经是0了,你获取width与height的方法不对。

jquery获取width与height应该这样写。
var width=$("#div").width();
var height=$("#div").height();

jquery获取width与height应该这样写。
var width=$("#div").width();
var height=$("#div").height();


谢谢版主大人已经被你解决了哈哈哈
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