php代码关于变量转义的问题
$('a.video', toolbar).click(function() { _this.save_bookmark(); _this.hide_menu(); $(this).xn_menu($('.video', menu), 0, 5000); setTimeout(function() { $('.video input.url', menu).focus().select(); }, 100); }); $('.video input.insert', menu).click(function() { var url = $('.video input.url', menu).val(); var width = $('.video input.w', menu).val(); var height = $('.video input.h', menu).val(); _this.add_video(url, width, height); return true; }); $('.video input.close', menu).click(function() { _this.hide_menu(); _this.load_bookmark(true); return true; });
this.add_video = function(url, width, height) { width = intval(width); height = intval(height); var s = "<br><br><center><script type=\"text/javascript\" src=\"jwplayer/jwplayer.js\"></script><div id=\"mediaplayer\"></div> <script type=\"text/javascript\">jwplayer('mediaplayer').setup({'flashplayer': 'jwplayer/jwplayer.flash.swf','image': 'http://7vzuer.com1.z0.glb.clouddn.com/t013d040a81b623566f.jpg', 'id': 'playerID', 'width': '100%', 'aspectratio':'10:6', 'title':'"+height+"', 'tracks':'"+width+"', 'file': '"+url+"' });</script><br><br></center>"; _this.paste(s); $('div.video', _this.menu).hide(); };
以上是两个变量 width 和 height 全部被变量转换成整型变量 了,我现在两个变量输出的都是0,文字和字母输入后都不显示应该是被转换的缘故,我想请朋友帮我改改这段代码,要求输出的两个变量 width 和 height
width 是URL形式的 height可以是文字 字幕 和数字形式(总之是去掉转型这块,代码我删除了转型的那两句但是依然还是输出的数值是0不知道怎么改了)
回复讨论(解决方案)
有没有人在啊?????????在线等
也没个人出来救救人
fasdfasfasdf
你这个是js,不是php
而js转整形的方法是parseInt 而不是intval, intval是php的方法
所以你的代码是错的。
var width = $('.video input.w', menu).val();
var height = $('.video input.h', menu).val();
这两个变量先打印出来看看是什么,估计这里就已经是0了,你获取width与height的方法不对。
jquery获取width与height应该这样写。
var width=$("#div").width();
var height=$("#div").height();
jquery获取width与height应该这样写。
var width=$("#div").width();
var height=$("#div").height();
谢谢版主大人已经被你解决了哈哈哈

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