有一个很难的有关问题,php获取javascript的值来判断域名来路,后期不好处理
有一个很难的问题,php获取javascript的值来判断域名来路,后期不好处理~
全部代码如下
首先你在浏览器中运行,打开控制台观察
http://localhost/test.php
<a href="test1.php">跳转到test1</a>
然后跳转到test1.php,代码
<?php<br />session_start();<br />require "./test2.php";<br />class A{<br /> function __construct()<br /> {<br /> $b=new B();<br /> $b->judge();<br /> }<br /> function judge()<br /> {<br /> if($_SESSION['status']==1){<br /> return true; <br /> }else{<br /> return false; <br /> }<br /> }<br /> function run()<br /> {<br /> if($this->judge()){<br /> echo 'success'; <br /> }else{<br /> echo 'error'; <br /> }<br /> }<br />}<br />$a=new A();<br />$a->run();<br />?>
作用是在执行A类方法的时候先判断域名来路,是否来自localhost,是的话,输出success,不是输出error
test2.php代码
<?php<br />session_start();<br />class B{<br /> function judge()<br /> {<br /> echo '<script><br /> var xmlhttp;<br /> if (window.ActiveXObject){<br /> xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");<br /> }else{<br /> xmlhttp = new XMLHttpRequest();<br /> }<br /> xmlhttp.open("POST", "./test3.php", true);<br /> xmlhttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");<br /> xmlhttp.send("data="+document.referrer);<br /> console.log(document.referrer); //控制台观察<br /> xmlhttp.onreadystatechange = function(){<br /> if (xmlhttp.readyState === 4 && xmlhttp.status === 200) {<br /> }<br /> };</script>';<br /> }<br />}<br />?>
test3.php,调用ajax执行文件
<?php<br />session_start();<br />if(stristr($_POST['data'], 'localhost')){<br /> $_SESSION['status']=1;<br /> }else{<br /> $_SESSION['status']='';<br /> }<br />?>
------解决方案--------------------
我能问一下你处理的问题是想要做什么,还是研究这个问题?因为我没看懂你要干什么,不好意思
------解决方案--------------------
说说你想想做什么?遇到了什么问题
------解决方案--------------------
看不明白需求,
你都是PHP文件,如果要知道前一页面来源,用$_SERVER['HTTP_REFERER']就可以了,有必要这么麻烦搞JS吗
------解决方案--------------------
整个请求都是可以伪造的
这样做确实会给伪造带来困难,但代码会变得很复杂...
------解决方案--------------------
可以变通一下,用cookie/session得到用户,得不到就报错。
如果用户请求太频繁就屏蔽请求。然后用缓存实现的话性能应该还可以。

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