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Detailed explanation of cases of taking integers and remainders in js (with code)
Detailed explanation of cases of taking integers and remainders in js (with code)
1.丢弃小数部分,保留整数部分
parseInt(5/2)
2.向上取整,有小数就整数部分加1
Math.ceil(5/2)
3,四舍五入.
Math.round(5/2)
4,向下取整
Math.floor(5/2)
Math 对象的方法
FF: Firefox, N: Netscape, IE: Internet Explorer
方法 描述 FF N IE
abs(x) 返回数的绝对值 1 2 3
acos(x) 返回数的反余弦值 1 2 3
asin(x) 返回数的反正弦值 1 2 3
atan(x) 以介于 -PI/2 与 PI/2 弧度之间的数值来返回 x 的反正切值 1 2 3
atan2(y,x) 返回从 x 轴到点 (x,y) 的角度（介于 -PI/2 与 PI/2 弧度之间） 1 2 3
ceil(x) 对一个数进行上舍入。 1 2 3
cos(x) 返回数的余弦 1 2 3
exp(x) 返回 e 的指数。 1 2 3
floor(x) 对一个数进行下舍入。 1 2 3
log(x) 返回数的自然对数（底为e） 1 2 3
max(x,y) 返回 x 和 y 中的最高值 1 2 3
min(x,y) 返回 x 和 y 中的最低值 1 2 3
pow(x,y) 返回 x 的 y 次幂 1 2 3
random() 返回 0 ~ 1 之间的随机数 1 2 3
round(x) 把一个数四舍五入为最接近的整数 1 2 3
sin(x) 返回数的正弦 1 2 3
sqrt(x) 返回数的平方根 1 2 3
tan(x) 返回一个角的正切 1 2 3
toSource() 代表对象的源代码 1 4 -
valueOf() 返回一个 Math 对象的原始值
代码案例：
<script type="text/javascript">
//取整
function getResult(num){
return parseInt(num);
}
//四舍五入到num后面的n位
function getResult(num,n){
return Math.round(num*Math.pow(10,n))/Math.pow(10,n);
}
//截取n位
function getresult(num,n){
return num.toString().replace(new RegExp("^(\\-?\\d*\\.?\\d{0,"+n+"})(\\d*)$"),"$1")+0;
}
</script>其他：
var mLength = textMn.length;
var mFirst = parseInt(mLength/60);
//取整
//alert(mLength);
var mLast = mLength; //取余
if(mLast>0){
$(".mood_content").height((mFirst+1)*20);
}相关文章：
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