How to submit data in JSON format to the server
This time I bring to you, what are the precautions when submitting JSON format data to the server. The following is a practical case, let's take a look.
Prepare Hero.java
public class Hero {
private String name;
private int hp;
public String getName() {
return name;
} public void setName(String name) {
this.name = name;
}
public int getHp() {
return hp;
}
public void setHp(int hp) {
this.hp = hp;
}
@Override
public String toString() {
return "Hero [name=" + name + ", hp=" + hp + "]";
}
}
public class Hero {
private String name;
private int hp;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getHp() {
return hp;
}
public void setHp(int hp) {
this.hp = hp;
}
@Override
public String toString() {
return "Hero [name=" + name + ", hp=" + hp + "]";
}
}submit.html文件
[html] view plain copy print?<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>用AJAX以JSON方式提交数据</title>
<script type="text/javascript" src="jquery.min.js"></script>
</head>
<body>
<form >
名称：<input type="text" id="name"/><br/>
血量：<input type="text" id="hp"/><br/>
<input type="button" value="提交" id="sender">
</form>
<p id="messagep"></p>
<script>
$('#sender').click(function(){
var name=document.getElementById('name').value;
var hp=document.getElementById('hp').value;
var hero={"name":name,"hp":hp};
var url="submitServlet";
$.post(
url,
{"data":JSON.stringify(hero)},
function(data) {
alert("提交成功，请在Tomcat控制台查看服务端接收到的数据");
});
});
</script>
</body>
</body>
</html>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>用AJAX以JSON方式提交数据</title>
<script type="text/javascript" src="jquery.min.js"></script>
</head>
<body>
<form >
名称：<input type="text" id="name"/><br/>
血量：<input type="text" id="hp"/><br/>
<input type="button" value="提交" id="sender">
</form>
<p id="messagep"></p>
<script>
$('#sender').click(function(){
var name=document.getElementById('name').value;
var hp=document.getElementById('hp').value;
var hero={"name":name,"hp":hp};
var url="submitServlet";
$.post(
url,
{"data":JSON.stringify(hero)},
function(data) {
alert("提交成功，请在Tomcat控制台查看服务端接收到的数据");
});
});
</script>
</body>
</body>
</html>The function of JSON.stringify function is to convert a javascript object into a string in JSON format.
Prepare SubmitServlet to receive data
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import net.sf.json.JSONObject;
public class SubmitServlet extends HttpServlet {
protected void service(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String data =request.getParameter("data");
System.out.println("服务端接收到的数据是：" +data);
JSONObject json=JSONObject.fromObject(data);
System.out.println("转换为JSON对象之后是："+ json);
Hero hero = (Hero)JSONObject.toBean(json,Hero.class);
System.out.println("转换为Hero对象之后是："+hero);
}
}
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import net.sf.json.JSONObject;
public class SubmitServlet extends HttpServlet {
protected void service(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String data =request.getParameter("data");
System.out.println("服务端接收到的数据是：" +data);
JSONObject json=JSONObject.fromObject(data);
System.out.println("转换为JSON对象之后是："+ json);
Hero hero = (Hero)JSONObject.toBean(json,Hero.class);
System.out.println("转换为Hero对象之后是："+hero);
}
}1. Get the string submitted by the browser
2. Convert the string into a JSON object
3 . Convert JSON object to Hero object
Finally configure web.xml
<?xml version="1.0" encoding="UTF-8"?> <web-app> <servlet> <servlet-name>SubmitServlet</servlet-name> <servlet-class>SubmitServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>SubmitServlet</servlet-name> <url-pattern>/submitServlet</url-pattern> </servlet-mapping> </web-app> <?xml version="1.0" encoding="UTF-8"?> <web-app> <servlet> <servlet-name>SubmitServlet</servlet-name> <servlet-class>SubmitServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>SubmitServlet</servlet-name> <url-pattern>/submitServlet</url-pattern> </servlet-mapping>
Start tomcat to access http://127.0.0.1:8080/project name/submit .html
#See the data coming from the tomcat console
I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!
Recommended reading:
What is the difference between wx:for and wx:for-item in WeChat mini program
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How does the Angular parent component call the child component
The above is the detailed content of How to submit data in JSON format to the server. For more information, please follow other related articles on the PHP Chinese website!
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