


JAVA implements precise addition, subtraction, multiplication and division codes
package lc.util; import java.math.BigDecimal; public class MathHelper { private static final int DEF_DIV_SCALE = 10; private MathHelper() { } /** * 提供精确的加法运算。 * * @param v1 * 被加数 * @param v2 * 加数 * @return 两个参数的和 */ public static double add(double v1, double v2) { BigDecimal b1 = new BigDecimal(Double.toString(v1)); BigDecimal b2 = new BigDecimal(Double.toString(v2)); return b1.add(b2).doubleValue(); } /** * 提供精确的减法运算。 * * @param v1 * 被减数 * @param v2 * 减数 * @return 两个参数的差 */ public static double sub(double v1, double v2) { BigDecimal b1 = new BigDecimal(Double.toString(v1)); BigDecimal b2 = new BigDecimal(Double.toString(v2)); return b1.subtract(b2).doubleValue(); } /** * 提供精确的乘法运算。 * * @param v1 * 被乘数 * @param v2 * 乘数 * @return 两个参数的积 */ public static double mul(double v1, double v2) { BigDecimal b1 = new BigDecimal(Double.toString(v1)); BigDecimal b2 = new BigDecimal(Double.toString(v2)); return b1.multiply(b2).doubleValue(); } /** * 提供(相对)精确的除法运算,当发生除不尽的情况时,精确到 小数点以后10位,以后的数字四舍五入。 * * @param v1 * 被除数 * @param v2 * 除数 * @return 两个参数的商 */ public static double div(double v1, double v2) { return div(v1, v2, DEF_DIV_SCALE); } /** * 提供(相对)精确的除法运算。当发生除不尽的情况时,由scale参数指 定精度,以后的数字四舍五入。 * * @param v1 * 被除数 * @param v2 * 除数 * @param scale * 表示表示需要精确到小数点以后几位。 * @return 两个参数的商 */ public static double div(double v1, double v2, int scale) { if (scale < 0) { throw new IllegalArgumentException( "The scale must be a positive integer or zero"); } BigDecimal b1 = new BigDecimal(Double.toString(v1)); BigDecimal b2 = new BigDecimal(Double.toString(v2)); return b1.divide(b2, scale, BigDecimal.ROUND_HALF_UP).doubleValue(); } /** * 提供精确的小数位四舍五入处理。 * * @param v * 需要四舍五入的数字 * @param scale * 小数点后保留几位 * @return 四舍五入后的结果 */ public static double round(double v, int scale) { if (scale < 0) { throw new IllegalArgumentException( "The scale must be a positive integer or zero"); } BigDecimal b = new BigDecimal(Double.toString(v)); BigDecimal one = new BigDecimal("1"); return b.divide(one, scale, BigDecimal.ROUND_HALF_UP).doubleValue(); } }

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