How to deal with default parameters in C++ function overloading?

In function overloading that handles default parameters, the compiler gives priority to the function version that best matches the actual parameters. If there is no matching function, an ambiguity error will occur. To avoid ambiguity, ensure that default arguments do not result in multiple matching functions.

Default parameter handling in C function overloading

Function overloading allows you to create objects with the same name by providing different parameter lists of multiple functions. When dealing with default arguments, it's important to understand how to instruct the compiler to choose a version of a function with specific default arguments.

Specify default parameters

Use the = operator to specify default parameters for function parameters:

void print(int num, string text = "Hello") {
  cout << text << ", " << num << endl;
}

In this code , the text parameter has the default value "Hello".

Function Selection

When an overloaded function with default parameters is called, the compiler will preferentially select the most specific version of the function, i.e. the one that best matches the actual parameter list Version.

Practical Case

Consider the following function overloading example:

void print(int num);
void print(int num, string text);

Now, let’s look at the behavior of two function calls:

• print(10): The compiler will select the first function without default parameters and output "10".
• print(10, "World"): The compiler will select the second function and output "World, 10".

Avoid ambiguity

Ensure that default parameters do not cause ambiguity in function overloading. If there is a function call matching more than one function, the compiler will generate an error.

Conclusion

By understanding how default parameters are handled, you can effectively use function overloading to write flexible and concise code.

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