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How to write a simple maze game in C++?

Nov 02, 2023 pm 06:44 PM
game c++ maze

How to write a simple maze game in C++?

How to write a simple maze game in C?

The maze game is a classic puzzle game that requires players to control a character to find the exit in the maze. In this article, we will learn how to program a simple maze game using C.

First, let's define the basic structure of the maze. We can use a two-dimensional array to represent the map of the maze, where 0 represents the wall, 1 represents the path, and 2 represents the end point. Here is an example of a maze map:

int maze10 = {

{0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{0, 1, 1, 1, 1, 1, 1, 1, 1, 0},
{0, 0, 0, 0, 1, 0, 0, 0, 1, 0},
{0, 1, 1, 0, 1, 0, 1, 1, 1, 0},
{0, 1, 0, 0, 1, 0, 1, 0, 0, 0},
{0, 1, 0, 1, 1, 1, 1, 0, 1, 0},
{0, 1, 1, 1, 0, 0, 1, 0, 1, 0},
{0, 0, 0, 0, 0, 1, 1, 0, 1, 0},
{0, 1, 1, 1, 1, 1, 0, 1, 1, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0}
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};

Next, we need to define a function to display the maze map. In this function, we use ASCII character graphics to represent the walls, paths, and end points of the maze. Here is an implementation example:

void displayMaze() {

for(int i = 0; i < 10; i++) {
    for(int j = 0; j < 10; j++) {
        if(maze[i][j] == 0) {
            cout << "# ";
        } else if(maze[i][j] == 1) {
            cout << "  ";
        } else if(maze[i][j] == 2) {
            cout << "E ";
        }
    }
    cout << endl;
}
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}

At the beginning of the game, we need to place the character at the starting point of the maze and change its position Represented as a variable. During the game, the player can use the up, down, left, and right arrow keys to control the movement of the character. Here is a sample code:

int playerX = 1;
int playerY = 1;

void movePlayer(char direction) {

if(direction == 'w' && maze[playerX - 1][playerY] != 0) {
    playerX--;
} else if(direction == 's' && maze[playerX + 1][playerY] != 0) {
    playerX++;
} else if(direction == 'a' && maze[playerX][playerY - 1] != 0) {
    playerY--;
} else if(direction == 'd' && maze[playerX][playerY + 1] != 0) {
    playerY++;
}
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}

In the main game loop, we need to constantly monitor the player's input and update the character's position and game state based on the input. The following is a sample code:

while(true) {

system("clear"); // 清空屏幕(适用于Linux/MacOS)
displayMaze(); // 显示迷宫地图

char input;
cin >> input;

movePlayer(input);

// 检查是否到达终点
if(maze[playerX][playerY] == 2) {
    cout << "Congratulations! You reached the exit." << endl;
    break;
}
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}

The above are the basic steps for writing a simple maze game using C. You can further expand the game by adding features such as timers, pedometers, and challenging levels. I hope you learn more about C programming through this project and have fun writing games!

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