


Python - Check if all characters in a string are alphanumeric?
要检查字符串中的所有字符是否都是字母数字,我们也可以使用 Python 和 Regex 中的 isalnum() 方法。首先,让我们了解什么是字母数字。
什么是字母数字?
字母数字包括字母和数字,即字母 (a-z) 和数字 (0-9)。示例:A、a、k、K、8、10、20 等
让我们看一个字母数字字符串的示例
8k9q2i3u4t
让我们看一个字符串示例,其中所有字符都不是字母数字 -
$$###k9q2i3u4t
使用 isalnum() 检查字符串中的所有字符是否都是字母数字
我们将使用内置的 isalnum() 方法来检查所有字符是否都是字母数字 -
# String1 mystr1 = "8k9q2i3u4t" # Display the string2 print("String = ",mystr1); # Check string1 for alphanumeric print("Is String1 alphanumeric = ",mystr1.isalnum()) # String2 mystr2 = "##$$9hnkh67" # Display the string2 print("\nString2 = ",mystr2); # Check string2 for alphanumeric print("Is String2 alphanumeric = ",mystr2.isalnum())
输出
String = 8k9q2i3u4t Is String1 alphanumeric = True String2 = ##$$9hnkh67 Is String2 alphanumeric = False
使用正则表达式检查字符串中的所有字符是否都是字母数字
要在Python中使用Regex,您需要安装re模块。要安装,请使用 pip
pip install re
要使用 re 模块,请导入它:
import re
现在让我们看一个例子
import re # String1 mystr1 = "m4w5r6" # Display the string2 print("String = ",mystr1); # Check string1 for alphanumeric print("Is String1 alphanumeic = ",bool(re.match('^[a-zA-Z0-9]+$', mystr1))) # String2 mystr2 = "pn#$nk2h1" # Display the string2 print("\nString2 = ",mystr2); # Check string2 for alphanumeric print("Is String2 alphanumeic = ",bool(re.match('^[a-zA-Z0-9]+$', mystr2)))
输出
String = m4w5r6 Is String1 alphanumeic = True String2 = pn#$nk2h1 Is String2 alphanumeic = False
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