Detailed explanation of ASP.NET's method of extracting multi-layer nested json data

This article mainly introduces the method of ASP.NET to extract multi-layer nested json data, and the method of using the third-party class library Newtonsoft.Json to extract multi-layer nested json data. Those who are interested can learn about it.

The example in this article describes the method of ASP.NET using the third-party class library Newtonsoft.Json to extract multi-layer nested json data. The specific example is as follows.

Assume that the json string that needs to be extracted is as follows:

{"name":"lily","age":23,"addr":{"city":guangzhou,"province":guangdong}}

First quote the namespace:

using Newtonsoft.Json;
using Newtonsoft.Json.Linq;

You can regard the above json string as an object, just write the corresponding class (if you use VS2013 for development, you can use "Edit--Paste Special--Paste JSON as a class" "Quickly convert json string to entity class)

 public class UserInfo
 {
  public string name;
  public int age;
  public address addr;
 }
 public class address
 {
  public string city;
  public string province;
 }

1. The code to convert json string to entity object is as follows:

string jsonData="{\"name\":\"lily\",\"age\":23,\"addr\":{\"city\":guangzhou,\"province\":guangdong}}";
UserInfo user=(UserInfo)JsonConvert.DeserializeObject(jsonData, typeof(UserInfo));

2. To read the value of an attribute in json, you can use the following code:

JObject jsonObj = JObject.Parse(jsonData);
string name=jsonObj ["name"].ToString();
string age=jsonObj ["age"].ToString();
string city=((JObject )jsonObj ["addr"])["city"].ToString();
string province=((JObject )jsonObj ["addr"])["province"].ToString();

3 , interpret multi-layer nested json, and get the value of any attribute:

If the json string that needs to be processed is as follows:

{"name":"lily","age":23,"addr":{"city":guangzhou,"province":guangdong}};

Then let If you input an object, such as "city", the system will output "guangzhou", and if you input "age", it will output "23". Since json is multi-level nested, it needs to be traversed one by one. The code is as follows:

  public string GetJsonValue(JEnumerable<JToken> jToken, string key)
  {
   IEnumerator enumerator = jToken.GetEnumerator();
   while (enumerator.MoveNext())
   {
    JToken jc = (JToken)enumerator.Current;
    if (jc is JObject || ((JProperty)jc).Value is JObject)
    {
     return GetJsonValue(jc.Children(), key);
    }
    else
    {
     if (((JProperty)jc).Name == key)
     {
      return ((JProperty)jc).Value.ToString();
     }
    }
   }
   return null;
  }

Code for calling GetJsonValue:

string jsonData = "{\"name\":\"lily\",\"age\":23,\"addr\":{\"city\":\"guangzhou\",\"province\":\"guangdong\"}}";
JObject jsonObj = JObject.Parse(jsonData);
Response.Write(GetJsonValue(jsonObj.Children(), "province"));

If it is a multi-layer nested array, you can also use the following code:

string jsonData = "{\"addr\":[{\"city\":\"guangzhou\",\"province\":\"guangdong\"},{\"city\":\"guiyang\",\"province\":\"guizhou\"}]}";
JObject jsonObj = JObject.Parse(jsonData);
JArray jar = JArray.Parse(jsonObj["addr"].ToString());
JObject j = JObject.Parse(jar[0].ToString());
Response.Write(j["city"]);

4. JSON to XML:

Copy the code The code is as follows:

string xmlstr=((XmlDocument)JsonConvert.DeserializeXmlNode(jsonData)).InnerXml.ToString();

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