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Home Backend Development PHP Tutorial php网站中,想通过输入一个域名,进到另一域名的界面,在线等

php网站中,想通过输入一个域名,进到另一域名的界面,在线等

Jun 23, 2016 pm 02:21 PM

php网站中,想通过输入一个域名,进到另一域名的界面,在线等

情况是:

对方有一个网站,名为www.abc.com/key/c


现须:我想输入 www.xy.com 能直接进入对方的网站内容,

(改域名配制文件和改php代码的方法都可以)
这怎么实现呢,
thanks.


回复讨论(解决方案)

最简单的方法是 header('Location: http://www.example.com/');

多谢楼上的,不行的,可能是我没说清
我想输入 www.xy.com 能直接进入对方(www.a.com/key/a)的网站内容,并显示的地址是www.xy.com
这怎么实现呢,

你这个是想做一个“欺骗”网站呀,估计正常方法是不行的,否则就乱套了呀。除非是在服务器上配置,运用转发。

试试iframe

用html 框架做

你这个是想做一个“欺骗”网站呀,估计正常方法是不行的,否则就乱套了呀。除非是在服务器上配置,运用转发。 +1

试试iframe +1 引用不经常用啊

这个要是那么简单实现的话 互联网域名还有什么用呢?控制你的目标机器 爱怎么打开就怎么打开


多谢楼上的,不行的,可能是我没说清
我想输入 www.xy.com 能直接进入对方(www.a.com/key/a)的网站内容,并显示的地址是www.xy.com
这怎么实现呢,

那你在www.xy.com页面写上
file_get_content('www.a.com/key/a');
不就可以获取内容的。


多谢楼上的,不行的,可能是我没说清
我想输入 www.xy.com 能直接进入对方(www.a.com/key/a)的网站内容,并显示的地址是www.xy.com
这怎么实现呢,

那你在www.xy.com页面写上
file_get_content('www.a.com/key/a');
不就可以获取内容的。

但是这样获取的内容很可能不行的,比如目标网站本来有ajax请求,这时就悲剧了。

想让正常运行,只能加个iframe。。

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