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Home Backend Development PHP Tutorial 查出当前id所在的页面

查出当前id所在的页面

Jun 23, 2016 pm 01:22 PM

字段id:   数值  1~27
分页时:每页显示 8数据
已知一个id,求这个id所在的页数

我的思路:

$arr=array();for(int i=0;i<maxpage;i++){$sql=(select id from table limit i*8,(i+1)*8);  $arr[$i]+=$this->db->getAll($sql);}$arr={[0]=>(1~8)[1]=>(9~16)[2]=>(17~24)[3]=>(25~27)}让id 与数组$arr的value 比较 ,相同的话 获取出 key后+1就是它所在的页面
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回复讨论(解决方案)

假定 id 连续,按 id 升序生成页面,则
$页号 = ceil($id / 8);

假定 id 连续,按 id 升序生成页面,则
$页号 = ceil($id / 8);


id不连续,用户有可能删除数据或被where过滤
有没有其它做法

不连续?那就需要知道 id 的分布情况

不连续?那就需要知道 id 的分布情况


id 的分布情况?
id就是不连续的

或者把数据库所有id都查出来,比较value,获取key,则 ceil((key+1)/8) 就是它所在的页数
如果数据多的多的话又很慢

已知一个id,求这个id在不连续id中正序的所在页数和位置(假设每页分X个)
eg
1: 已知id=5 id{1,2,5,9,10}, X=2 那么 已知id在第二页的第一个位置
2: 已知id=9 id{1,2,3,7,9,10} X=2 那么 已知id在第三页的第一个位置

这种只能是把所有的id取出来,
然后按 顺序编号,

然后得到指定id的编号,
$页号 = ceil( $编号 / 8);

有了 id 的分布,那就好计算了

//已知id=5   id{1,2,5,9,10},  X=2   那么 已知id在第二页的第一个位置$id = 5;$a = array(1,2,5,9,10);$x = 2;$p = array_search($id, $a);echo ceil($p / $x) + 1; //2//已知id=9   id{1,2,3,7,9,10}  X=2  那么  已知id在第三页的第一个位置$id = 9;$a = array(1,2,5,9,10);$x = 2;$p = array_search($id, $a);echo ceil($p / $x) + 1; //3
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如果 id 是乱序的,一样也可计算
$id = 9;$a = array(1,5,9,2,10);$x = 2;$p = array_search($id, $a);echo ceil($p / $x) + 1; //2
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这种只能是把所有的id取出来,
然后按 顺序编号,

然后得到指定id的编号,
$页号 = ceil( $编号 / 8);



数据多的话,这种方法不好

或者 我求出最大页 第一页~最大页 获取第一个id 让已知id和第一个id进行比较 求出页数


这种只能是把所有的id取出来,
然后按 顺序编号,

然后得到指定id的编号,
$页号 = ceil( $编号 / 8);



数据多的话,这种方法不好

或者 我求出最大页 第一页~最大页 获取第一个id 让已知id和第一个id进行比较 求出页数



关键是你的需求,id是不连续的,你怎么知道每一页的第一个id是多少?
一样必须进行顺序编号,
不过简单一点,就是只 select 出0~指定id,就ok了



关于id这一块
1.一次性把所有id查询出来
2.从第一页到最大页
判断第一页第一个id 是否<已知id 是的话第二页第一个id 是否<已知id ........
这样查出来的数据好像少了些,但是db用的次数就多了
我还是用1把功能做出来先,如果有好的有方法告诉我,让我参考下

既然是要查询数据库,那么可以这样做

select id, ceil(@s/每页行数) as page, @s:=@s+1 from 表, (select @s:=1) t HAVING id=$id
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查询结果中的 page 列就是 id 对应的页号

有点问题,这样才对

select id, page   from (select id, ceil(@s/每页行数) as page, @s:=@s+1 from 表, (select @s:=1) t ) t1  where id=$id
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有点问题,这样才对

select id, page   from (select id, ceil(@s/每页行数) as page, @s:=@s+1 from 表, (select @s:=1) t ) t1  where id=$id
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@一般用来表示自己定义的一个变量
“:=”主要是用于传递外部参数为语句中变量赋值

@s:=@s+1 @s:=1 变量赋值两次?
(select @s:=1) t ) t1 t,t1没看懂

这种技巧性的写法要看悟性了
正常的写法是

set @s:=1;select id, ceil(@s/每页行数) as page, @s:=@s+1 from 表
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但出于防止sql攻击的考虑,php 不允许同时执行两条及以上指令,所以使用了笛卡尔连接
(select @s:=1) t  只是为了给用户变量 @s 赋初值

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