Table of Contents
序言
需求分析
效果图
代码分析
常见问题
Home Backend Development PHP Tutorial 阐述在Yii2上实现跳转提示页

阐述在Yii2上实现跳转提示页

Jun 23, 2016 pm 01:06 PM

序言

为了让用户有更加良好的体验,在操作成功或者失败后,来个提示并跳转页面,我就在Yii2上实现了这一个效果。在写这个跳转提示页的时候,找资料我发现网上关于这方面的中文资料真的很少,大家也都共享下吧!

需求分析

1、用户在操作成功或者失败后,来个提示并跳转页面。2、使用这种方式$this->success(),$this->error()调用(仿造Yii2自带 $this->render()加载页面的方式)。

效果图

样式有点丑,但是功能是好的,要是不喜欢这样式大家可以自行美化一下!

代码分析

1、在控制器的基类Controller.php里边增加两个方法,这么写:

/**     * 通用成功跳转       * @param unknown $url 成功后跳转的URL     * @param number $sec 自动跳转秒数     * @return Ambigous <string, string>     */     public function success($url= [] ,$sec = 3){          $url= empty($url)? ['/admin/main']: $url;        $url= /yii/helpers/Url::toRoute($url);        return $this->renderPartial('../base/msg',['gotoUrl'=>$url,'sec'=>$sec]);    }       /**     * 通用错误跳转     * @param string $msg 错误提示信息     * @param number $sec     * @return Ambigous <string, string>     */    public function error($msg= '',$sec = 3){        return $this->renderPartial('../base/msg',['errorMessage'=>$msg,'sec'=>$sec]);    }
Copy after login

2、在loginviewsbase的下面建立一个命名为msg.php的页面,代码如下:

<?php/* @var $this yii/web/View *//* @var $name string *//* @var $message string *//* @var $exception Exception */use yii/helpers/Html;?><div class="site-error">    <div class="alert alert-danger page-none-alert">        <p>        <?php if(isset($errorMessage)):?>            <span class="glyphicon glyphicon-remove-sign text-danger"></span>            <span class="btn-lg text-danger"><?php echo '操作出错啦!' ?></span>            <?php echo '<p>'.$errorMessage.'</p>';?>        <?php else:?>            <span class="glyphicon glyphicon-ok-sign text-success"></span>            <span class="btn-lg text-success">恭喜!操作成功!</span>        <?php endif;?>    </p>            <p class="text-muted">该页将在3秒后自动跳转!</p>    <p>        <?php if(isset($gotoUrl)):?>            <a href="<?php echo $gotoUrl?>">立即跳转</a>        <?php else:?>            <a href="javascript:void(0)" onclick="history.go(-1)">返回上一页</a>        <?php endif;?>    </p>        </div>   <style>   .page-none-alert{margin: 100px 0 !important;    text-align: center !important;    font-size: 30px !important;}   </style> </div><script>  <?php if(!isset($gotoUrl)):?>    setInterval("history.go(-1);",<?php echo $sec;?>000); <?php else:?>   setInterval("window.location.href='<?php echo  $gotoUrl;?>'",<?php echo $sec;?>000);<?php endif;?></script>
Copy after login

3、完成以上步骤之后就可以在login模块下的控制器里边直接调用了,调用方式如下:

成功的调用方式: return $this->success([‘/site/login’]);

失败的调用方式: return $this->error(‘数据修改失败!’);

常见问题

1、跳转提示的JS写在如下我注释的地方了,写在那的话就不起作用了,得写在外面才行。

 <?php $this->beginBlock('JUMP_JS')?>        (function(){           //跳转提示的JS写在这了。不能写在这,写在这里就不起作用了。         });<?php        $this->endBlock();        $this->registerJs($this->blocks['JUMP_JS'],/yii/web/view::POS_END);?>        
Copy after login
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