阐述在Yii2上实现跳转提示页
序言
为了让用户有更加良好的体验,在操作成功或者失败后,来个提示并跳转页面,我就在Yii2上实现了这一个效果。在写这个跳转提示页的时候,找资料我发现网上关于这方面的中文资料真的很少,大家也都共享下吧!
需求分析
1、用户在操作成功或者失败后,来个提示并跳转页面。2、使用这种方式$this->success(),$this->error()调用(仿造Yii2自带 $this->render()加载页面的方式)。
效果图
样式有点丑,但是功能是好的,要是不喜欢这样式大家可以自行美化一下!
代码分析
1、在控制器的基类Controller.php里边增加两个方法,这么写:
/** * 通用成功跳转 * @param unknown $url 成功后跳转的URL * @param number $sec 自动跳转秒数 * @return Ambigous <string, string> */ public function success($url= [] ,$sec = 3){ $url= empty($url)? ['/admin/main']: $url; $url= /yii/helpers/Url::toRoute($url); return $this->renderPartial('../base/msg',['gotoUrl'=>$url,'sec'=>$sec]); } /** * 通用错误跳转 * @param string $msg 错误提示信息 * @param number $sec * @return Ambigous <string, string> */ public function error($msg= '',$sec = 3){ return $this->renderPartial('../base/msg',['errorMessage'=>$msg,'sec'=>$sec]); }
2、在loginviewsbase的下面建立一个命名为msg.php的页面,代码如下:
<?php/* @var $this yii/web/View *//* @var $name string *//* @var $message string *//* @var $exception Exception */use yii/helpers/Html;?><div class="site-error"> <div class="alert alert-danger page-none-alert"> <p> <?php if(isset($errorMessage)):?> <span class="glyphicon glyphicon-remove-sign text-danger"></span> <span class="btn-lg text-danger"><?php echo '操作出错啦!' ?></span> <?php echo '<p>'.$errorMessage.'</p>';?> <?php else:?> <span class="glyphicon glyphicon-ok-sign text-success"></span> <span class="btn-lg text-success">恭喜!操作成功!</span> <?php endif;?> </p> <p class="text-muted">该页将在3秒后自动跳转!</p> <p> <?php if(isset($gotoUrl)):?> <a href="<?php echo $gotoUrl?>">立即跳转</a> <?php else:?> <a href="javascript:void(0)" onclick="history.go(-1)">返回上一页</a> <?php endif;?> </p> </div> <style> .page-none-alert{margin: 100px 0 !important; text-align: center !important; font-size: 30px !important;} </style> </div><script> <?php if(!isset($gotoUrl)):?> setInterval("history.go(-1);",<?php echo $sec;?>000); <?php else:?> setInterval("window.location.href='<?php echo $gotoUrl;?>'",<?php echo $sec;?>000);<?php endif;?></script>
3、完成以上步骤之后就可以在login模块下的控制器里边直接调用了,调用方式如下:
成功的调用方式: return $this->success([‘/site/login’]);
失败的调用方式: return $this->error(‘数据修改失败!’);
常见问题
1、跳转提示的JS写在如下我注释的地方了,写在那的话就不起作用了,得写在外面才行。
<?php $this->beginBlock('JUMP_JS')?> (function(){ //跳转提示的JS写在这了。不能写在这,写在这里就不起作用了。 });<?php $this->endBlock(); $this->registerJs($this->blocks['JUMP_JS'],/yii/web/view::POS_END);?>

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