PHP采集代码
PHP采集代码求助
我想采集这个网站的列表商品http://www.taomanzu.com/category-16-4-1-10000-1.html,功能是,同时能采集商品的ID,和商品的名称,并且写入缓存中,如http://www.taomanzu.com/category-16-4-1-10000-1.html列表中的某个商品ID是:9914540199,标题是:纯棉磨毛卷边九分裤\工装九分裤\休闲九分裤 2色
让后我需要的是同时能采集到商品ID,和商品标题,能合成一个链接如
纯棉磨毛卷边九分裤\工装九分裤\休闲九分裤 2色
下面的这代码只能采集商品ID或者标题,请问如何修改才可以同时采集并且合并成一个链接!
- PHP code
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --><?php //今日热门,10分钟更新一次 require 'global.php'; require 'gzdoc.php'; include 'config.php'; $id=$_GET["id"]; $pg=$_GET["pg"]; if($_GET['pg']==""){ $pg=0; } $dir='cache'; if(!file_exists($dir)){ @mkdir($dir,0777); } ob_start(); //女装 $lastflesh=@filemtime($dir."/Cache_NvZhuang_new.html"); if(!file_exists($dir."/Cache_NvZhuang_new.html") or ($lastflesh + ($flush * 60 * 60) <= $timestamp)){ //$flush * 60 一小时 $openurl="http://www.taomanzu.com/category-16-4-1-10000-1.html"; $file = curl($openurl); //开始处理一条一条的条数!!! $result=''; if (preg_match_all('/<p class="taoke_title"><a href="tshow-(.*?).html" target="_blank">/is', $file, $list)) { foreach ($list[1] as $i=>$k1 ) if ($i'.$k1.'</a>'; } } $result_utf=iconv("GB2312","GB2312",$result); file_put_contents($dir."/Cache_NvZhuang_new.html",$result_utf); } else { } ?> <?php GzDocOut; ?>
------解决方案--------------------
把你的正则表达式换成

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