Home Backend Development Python Tutorial How to remove keys in three-layer nested dictionary with the innermost value of the same dictionary in Python?

How to remove keys in three-layer nested dictionary with the innermost value of the same dictionary in Python?

Apr 01, 2025 pm 08:30 PM
python

How to remove keys in three-layer nested dictionary with the innermost value of the same dictionary in Python?

In Python programming, handling nested dictionaries is a common operation. This article discusses how to remove keys with exactly the same value from a three-layer nested dictionary.

Problem Description: Given a three-layer nested dictionary, its innermost dictionary may have the same value. The goal is to delete all keys with exactly the same innermost dictionary value.

Example:

Enter dictionary:

 dict1 = {'l1':{'pop1':{'a':1}, 'pop2':{'a':1}, 'pop3':{'a':1}},
         'l2':{'pop1':{'b':1}, 'pop2':{'b':1}, 'pop3':{'b':2}},
         'l3':{'pop1':{'c':1}, 'pop2':{'c':2}, 'pop3':{'c':3}}}
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Expected output dictionary:

 dict2 = {'l2':{'pop1':{'b':1}, 'pop2':{'b':1}, 'pop3':{'b':2}},
         'l3':{'pop1':{'c':1}, 'pop2':{'c':2}, 'pop3':{'c':3}}}
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In dict1 , the innermost dictionary values ​​corresponding to the 'l1' key are {'a':1} , so 'l1' needs to be deleted.

Challenge: Using the set directly to determine whether the dictionary value is the same will cause an error, because the dictionary is not hashable.

Solution: Solve by traversing the dictionary and comparing the innermost dictionary values ​​one by one.

Code:

 def remove_identical_inner_dicts(input_dict):
    """
    Delete keys with exactly the same inner dictionary value in three-layer nested dictionary.

    Args:
        input_dict: The three-layer nested dictionary entered.
    """
    # Create a copy to avoid modifying the original dictionary working_dict = input_dict.copy() 

    for key, value in working_dict.items():
        inner_dicts = list(value.values()) # Get all inner dictionaries if all(inner_dicts[0] == inner_dict for inner_dict in inner_dicts): # Determine whether all inner dictionaries are the same del input_dict[key] # Delete the key in the original dictionary# Test code dict1 = {'l1':{'pop1':{'a':1}, 'pop2':{'a':1}, 'pop3':{'a':1}},
         'l2':{'pop1':{'b':1}, 'pop2':{'b':1}, 'pop3':{'b':2}},
         'l3':{'pop1':{'c':1}, 'pop2':{'c':2}, 'pop3':{'c':3}}}

remove_identical_inner_dicts(dict1)
print(dict1) # output dict2
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This function first copies the input dictionary and then iterates over each item. It extracts all inner dictionaries and uses the all() function to check if they are exactly the same. If so, remove the corresponding key from the original dictionary. This avoids the error of iterating while modifying the dictionary.

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