


What are the most efficient ways to sum the digits of a number?
Summating Digits of a Number: Exploring Efficient Approaches
When aiming to ascertain the total sum of digits in a numerical input, various methodologies can be employed. While initial instinct may lead to utilizing a string-based approach, converting the number to a string and then applying mathematical operations on each individual digit, this method can be sub-optimal.
A more efficient technique lies in manipulating the number as an integer. This can be achieved through a while loop that iterates through the digits of the number, repeatedly extracting the last digit (using the modulo operator) and adding it to a running total while excluding that digit (through integer division). This method, known as the modulo-and-divide approach, is exemplified in the following code snippet:
def sum_digits(n): s = 0 while n: s += n % 10 n //= 10 return s
For further optimization, one can employ the divmod() function, which simultaneously performs the modulo and integer division operations:
def sum_digits2(n): s = 0 while n: n, remainder = divmod(n, 10) s += remainder return s
Furthermore, a single assignment statement can be utilized to improve execution speed by combining the summation and division operations:
def sum_digits3(n): r = 0 while n: r, n = r + n % 10, n // 10 return r
Benchmarking these approaches reveals that the modulo-and-divide method outperforms the string manipulation techniques, while the single assignment version emerges as the swiftest option:
%timeit sum_digits(n) 1000000 loops, best of 3: 574 ns per loop %timeit sum_digits2(n) 1000000 loops, best of 3: 716 ns per loop %timeit sum_digits3(n) 1000000 loops, best of 3: 479 ns per loop %timeit sum(map(int, str(n))) 100000 loops, best of 3: 1.42 us per loop %timeit sum([int(digit) for digit in str(n)]) 100000 loops, best of 3: 1.52 us per loop %timeit sum(int(digit) for digit in str(n)) 100000 loops, best of 3: 2.04 us per loop
Therefore, when seeking to efficiently sum the digits of a number, it is advisable to opt for the modulo-and-divide technique or even the single assignment variant for maximum performance.
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