Home Web Front-end JS Tutorial Can JavaScript\'s Loose Equality (==) Ever Make (a == 1 && a == 2 && a == 3) True?

Can JavaScript\'s Loose Equality (==) Ever Make (a == 1 && a == 2 && a == 3) True?

Nov 03, 2024 am 06:35 AM

Can JavaScript's Loose Equality (==) Ever Make (a == 1 && a == 2 && a == 3) True?

Is (a== 1 && a ==2 && a==3) Ever True?

Question:

Can the expression (a== 1 && a ==2 && a==3) ever evaluate to true in JavaScript, despite the logical inconsistency?

Understanding Expression Evaluation:

Normally, the expression (a== 1 && a ==2 && a==3) would always evaluate to false because the value of 'a' cannot simultaneously be 1, 2, and 3. However, JavaScript's equality operator (==) has some quirks when dealing with non-primitive values like objects.

Custom Value Conversion:

JavaScript allows objects to define their own toString() or valueOf() functions, which are used to convert the object to a primitive value for comparison purposes. By leveraging this, it's possible to create an object that changes its value each time it is converted.

Custom Object with Dynamic toString() Function:

Consider the following object:

<code class="js">const a = {
  i: 1,
  toString: function () {
    return a.i++;
  }
}</code>
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This object has a property 'i' and a custom toString() function. Each time the object is converted to a primitive value (e.g., via == or console.log()), the toString() function is called, returning the current value of 'i' and incrementing it.

Expression Evaluation Trick:

Using this custom object, the expression (a == 1 && a == 2 && a == 3) can now evaluate to true:

<code class="js">if(a == 1 && a == 2 && a == 3) {
  console.log('Hello World!');
}</code>
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The first comparison (a == 1) returns true because the toString() function returns 1. The second comparison (a == 2) also returns true because the toString() function is called again, returning 2. Similarly, the third comparison (a == 3) returns true, resulting in the entire expression evaluating to true.

Conclusion:

While it may seem counterintuitive, it is possible for (a== 1 && a ==2 && a==3) to evaluate to true in JavaScript by creating a custom object that dynamically changes its value on conversion. This demonstrates the potential for unexpected behavior when dealing with non-primitive values in JavaScript.

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