mysql中GROUP BY分组取前N条记录实现
GROUP BY之后如何取每组的前两位下面我来讲述mysql中GROUP BY分组取前N条记录实现方法。
代码如下 | 复制代码 |
mysql> select * from t_subject; SELECT uid, group_concat(subject)
| uid | group_concat(a.subject) | |
----我想要的是如下效果的 该怎么写啊(就是取出分组后每组的前三条记录)---
代码如下 | 复制代码 |
| uid | group_concat(a.subject) | | 1 | aa,ff,mm | | 2 | yy,rr,ee | | 3 | kk,pp,xx | | 4 | nn,dd,vv | |
实例二
mysql中GROUP BY分组取前N条记录实现
mysql分组,取记录
GROUP BY之后如何取每组的前两位下面我来讲述mysql中GROUP BY分组取前N条记录实现方法。
这是测试表(也不知道怎么想的,当时表名直接敲了个aa,汗~~~~):
结果:
方法一:
代码如下 | 复制代码 |
SELECT a.id,a.SName,a.ClsNo,a.Score FROM aa a LEFT JOIN aa b ON a.ClsNo=b.ClsNo AND a.Score |
拆开分析:
1、 LEFT JOIN aa b ON a.ClsNo=b.ClsNo AND a.Score 同一个班级(每个班级四个人),分数比当前学生高的记录,那就意味这成绩垫底的学生,将会产生三条记录 2、 group by a.id,a.SName,a.ClsNo,a.Score having count(b.id)
a.id,a.SName,a.ClsNo,a.Score可以代表一个学生(以学生分组),如果count(b.id)
这个我觉得是比较有意思的,取每一条记录,判断同一个班级,大于当前成绩的同学是不是小于2个人。 这种方式进过测试不通过,ERROR 1235 (42000): This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery' ,不能在这几个子查询中使用limit。
方法二:
代码如下
复制代码
SELECT * FROM aa a WHERE 2>(SELECT COUNT(*) FROM aa WHERE ClsNo=a.ClsNo and Score>a.Score) ORDER BY a.ClsNo,a.Score DESC;
方法三:
代码如下
复制代码
SELECT * FROM aa WHERE id IN (SELECT id FROM aa WHERE ClsNo=a.ClsNo ORDER BY Score DESC LIMIT 2) ORDER BY a.ClsNo,a.Score DESC;

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