Hive的UDF实现类似于Oracle的decode函数功能
Oracle的decode函数语法:DECODE(value,if1,then1,if2,thne2,if3,then3,...else)。首先涉及到的问题是输入参数的动态化,decode函
客户提的要求,让用hive实现类似orale的decode函数功能。好吧,开工。
Oracle的decode函数语法:DECODE(value,if1,then1,if2,thne2,if3,then3,...else)。
首先涉及到的问题是输入参数的动态化,decode函数要求输入函数是偶数个,然后实现类似if,else的逻辑判断功能。这样的话用到了java的Object ... args 来传入多个参数,然后在方法中检测个数是否符合偶数个。选用Object类型的原因就是为了参数类型的动态识别。
为了实现对decode(1,1.0,'a',2.0,'b','c')的判断类型,需要将Integer类型的转换为double类型,不然的话这样的内容就无法实现。用instanceof 检测输入的参数类型,,来判断。
相关阅读:
基于Hadoop集群的Hive安装
Hive内表和外表的区别
Hadoop + Hive + Map +reduce 集群安装部署
Hive本地独立模式安装
Hive学习之WordCount单词统计
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import org.apache.hadoop.hive.ql.exec.UDF;
public class Decode extends UDF {
public String evaluate(Object... args) {
if (args.length % 2 != 0) {
System.out.println("输入的参数个数错误,应为偶数");
}
int number = args.length;
Object result = null;
int flag = number - 1;
int i = 1;
if (args[0] instanceof Integer) {
args[0] = Double.valueOf(Integer.valueOf(args[0].toString()));
}
while (i
if (args[i] instanceof Integer) {
args[i] = Double.valueOf(Integer.valueOf(args[i].toString()));
}
if (String.valueOf(args[i]).equals(String.valueOf(args[0]))) {
result = args[i + 1];
break;
} else {
i += 2;
}
}
if (result == null)
result = args[flag];
return String.valueOf(result);
}
}
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Hive 的下载地址:请点这里
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