Discuz Uchome ajaxpost小技巧
discuz的ajaxpost功能有点强大,但缺点也很明显,如果ajaxpost提交一个FORM,那么返回的时候只能显示showmessage的内容,而不会主动跳转,因此这里就有一个小技
比如默认submit按钮这样操作:onclick="ajaxpost('formid')";之类的,我们可以先这样。。
onclick="$('__formid').innerText='';ajaxpost('formid');checkPostResult();";
含义其实很简单,先把ajaxpost提示信息所在的div内容清空。然后提交。最后,根据返回值来判断。。
复制代码 代码如下:
function checkPostResult(){
var cid = setInterval(function(){
if( $('__formid').innerText == 'success'){
alert('提交成功');
location.href='xxxxx.php';
clearInterval(cid);
}
},1000);
}
这个处理也很简单,香港服务器,为什么是用setInterval和clearInterval,主要是由于ajax是异步操作,如果不用setInterval方法 ,那么在ajaxpost结束的时候,香港空间,其实提示信息还没有append到提示信息所在的ID里,所以用setInterval方法先延迟然后循环处理最后再结束提示。。。
clearInterval用的不太对,香港空间,但短时间内想不到更好的。先这样临时解决喽。

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