python3.x - 如何让base64在python2和python3都运行通过

Question

args = [1,2,3,4]
text = json.dumps(args)
query = base64.b64encode(text)
auth = hashlib.md5(query).hexdigest()
print(auth)

这段代码在python2.7下面通过，但是python3.5会报错：
TypeError: 'str' does not support the buffer interface

更改为这样以后，python3可以通过了

args = [1,2,3,4]
text = json.dumps(args)
query = base64.b64encode(bytes(text, 'utf-8'), )
auth = hashlib.md5(query).hexdigest()
print(auth)

但是python2又会报错：
TypeError: str() takes at most 1 argument (2 given)

该怎样修改才能使代码在python2和python3都运行通过呢？

Answer 1

import base64, json, hashlib

args = [1,2,3,4]
text = json.dumps(args)
try:
    text = bytes(text, 'utf-8')
except:
    pass
query = base64.b64encode(text)
auth = hashlib.md5(query).hexdigest()
print(auth)

Answer 2

args = [1,2,3,4]
text = json.dumps(args)

#这里添加了一个bytearray类型的变量temp
temp = bytearray(text, encoding='ascii')

query = base64.b64encode(temp)
auth = hashlib.md5(query).hexdigest()
print(auth)

Answer 3

import base64, json, hashlib, sys

args = [1, 2, 3, 4]
text = json.dumps(args)
if sys.version_info > (3, 0):
    text = bytes(text, 'utf-8')
query = base64.b64encode(text)
auth = hashlib.md5(query).hexdigest()
print(auth)