pymysql - python3.5操作数据库中fetchall的问题

Question

import pymysql.cursors
import networkx as nx

Connect to the database

connection = pymysql.connect(host='localhost',

                         port=3306,
                         user='root',
                         password='',
                         db='shortest',
                         charset='utf8mb4',
                         cursorclass=pymysql.cursors.DictCursor)

执行sql语句

try:

    cursor = connection.cursor()
    # 执行sql语句，进行查询
    sql = 'SELECT author1,author2,year FROM shortest WHERE id < 200'
    cursor.execute(sql)
    # 获取查询结果
    result = cursor.fetchall()
    for row in result:
        author1 = row[1]
        author2 = row[2]
        year = row[3]
        # 打印结果
        print
        "auther1=%s,author2=%s,year=%s" % \
        (myauther1, myauther2, myyear)
    # 没有设置默认自动提交，需要主动提交，以保存所执行的语句
    connection.commit()

finally:

connection.close();

这个代码我感觉没有问题，但是编译器却报错！！！
Traceback (most recent call last):
File "E:/Python Work/beta1/test.py", line 21, in <module>

author1 = row[1]

KeyError: 1

希望高手可以解释指点一下，谢谢啦！

Answer 1

应该是result是一个字典结构，在python中需要用dict['Name']这样的形式使用吧。具体可百度字典用法。

Answer 2

你先把result打印出来试试