python3.x - python3遇到了OSError: [Errno 22] Invalid argument

Answer 1

下面这句写错了：
txt_again=open(r'"E:\ource code\python\ex15_sample.txt"')
应该是：
txt_again=open(r'E:\source code\python\ex15_sample.txt')

Answer 2

下面这句写错了：
txt_again=open(r'"E:\source code\python\ex15_sample.txt"')
应该是：
txt_again=open(r'E:\\source code\python\ex15_sample.txt')