[已解决]输入一组数 判定奇偶个数 附源码 求问为什么不能循环（java）

Question

1.你的程序要读入一系列正整数数据，输入-1表示输入结束，-1本身不是输入的数据。程序输出读到的数据中的奇数和偶数的个数。
2.源码如下

package count;
 
import java.util.Scanner;
 
public class Count {
 
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner in = new Scanner(System.in);
        int number = 0;
        int count = 0;
        int digit = 0;
        number = in.nextInt();
        while ( number != -1)
        {
            int a = number % 10;
            if (a % 2 == 0) 
            {
                count = count + 1;
            }else 
            {
                digit = digit + 1;
            }
            number = number / 10;   
            if (number == 0)
            break;
        }
        System.out.println(count );
        System.out.println(digit);
    }
}

3.为什么直接输出1和0 不循环呢？

Answer 1

public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner in = new Scanner(System.in);
        int number = 0;
        int count = 0;
        int digit = 0;
        number = in.nextInt();
        int out = 10;
        while ( number != -1 )
        {
            int a = number % 10;
            if (a % 2 == 0)
            {
                System.out.println("偶数 : "+number);
                count = count + 1;
            }else
            {
                System.out.println("奇数 : "+number);
                digit = digit + 1;
            }
            number = number / 10;
            System.out.println("number / 10 : "+number);
            if(number==0){
                number = in.nextInt();
            }
        }
        System.out.println(count);
        System.out.println(digit);
    }

修改了下代码，不知道是否是你想要的。

Answer 2

public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int number = 0;
        int count = 0;
        int digit =0;
        String str=in.nextLine();
        String[] arr=str.split(" ");
        int[] numberArr=new int[arr.length];
        for (int i = 0; i < numberArr.length; i++) {
            try {
                numberArr[i]=Integer.parseInt(arr[i]);
            } catch (Exception e) {
                System.out.println("数据转换异常");
            }
            number=numberArr[i];
            int a = number % 10;
            if (a % 2 == 0) 
            {
                count = count + 1;
            }else 
            {
                digit = digit + 1;
            }
            number = number / 10; 
        }
       
        System.out.println(count );
        System.out.println(digit);
    
    }
    我用了nextLine希望能对你有帮助