python - django orm 代码长时怎么分行的

Question

entry = Entry.objects.filter(columnA=1, columnC=2, columnB=3).values(columnA, columnB, columnC).orderby(columnA, columnB, columnC)

django 官方示例好像是

entry = Entry.objects.filter(
                columnA=1, columnC=2, columnB=3
            ).values(
                columnA, columnB, columnC
            ).orderby(
                columnA, columnB, columnC
            )         
            

有其他好的书写方法吗

Answer 1

entry = Entry.objects.filter(columnA=1, columnC=2, columnB=3) \
                     .values(columnA, columnB, columnC) \
                     .orderby(columnA, columnB, columnC)

这个如何?