;WITH good(id,[name],cateId)AS(
SELECT 1,'A',1 UNION ALL
SELECT 2,'B',1 UNION ALL
SELECT 3,'C',2 UNION ALL
SELECT 4,'D',2 UNION ALL
SELECT 5,'E', 3 UNION ALL
SELECT 6,'R',3 UNION ALL
SELECT 7,'G',4 UNION ALL
SELECT 8,'H',4 UNION ALL
SELECT 9,'R',4 UNION ALL
SELECT 10,'GG',4 UNION ALL
SELECT 11,'HH',4 UNION ALL
SELECT 12,'RR',4 UNION ALL
SELECT 13,'Y',4
)
SELECT * FROM (
SELECT *,ROW_NUMBER()OVER(PARTITION BY g.cateId ORDER BY id) AS rn
FROM good AS g WHERE g.cateId BETWEEN 1 AND 5
) t WHERE rn<=5
分类4实际多余5条,但查询仅返回五条 id name cateId rn ----------- ---- ----------- -------------------- 1 A 1 1 2 B 1 2 3 C 2 1 4 D 2 2 5 E 3 1 6 R 3 2 7 G 4 1 8 H 4 2 9 R 4 3 10 GG 4 4 11 HH 4 5
如果不同分类要返回不同的行,下面是分类1,2,3最多返回2条其他最多返回5条
;WITH good(id,[name],cateId)AS(
SELECT 1,'A',1 UNION ALL
SELECT 2,'B',1 UNION ALL
SELECT 3,'C',2 UNION ALL
SELECT 4,'D',2 UNION ALL
SELECT 5,'E', 3 UNION ALL
SELECT 6,'R',3 UNION ALL
SELECT 7,'G',4 UNION ALL
SELECT 8,'H',4 UNION ALL
SELECT 9,'R',4 UNION ALL
SELECT 10,'GG',4 UNION ALL
SELECT 11,'HH',4 UNION ALL
SELECT 12,'RR',4 UNION ALL
SELECT 13,'Y',4
)
SELECT * FROM (
SELECT *,ROW_NUMBER()OVER(PARTITION BY g.cateId ORDER BY id) AS rn
FROM good AS g WHERE g.cateId BETWEEN 1 AND 5
) t WHERE rn<=case WHEN cateId IN (1,2,3) then 2 ELSE 5 END
如果是MYSQL,没有ROW_NUMBER,可以参考下面这样实现ROW_NUMBER()OVER(PARTITION BY
SELECT @row_num := IF(@prev_value=cateId,@row_num+1,1) AS rn
,id,[name],cateId
,@prev_value := cateId
FROM good,
(SELECT @row_num := 1) x,
(SELECT @prev_value := '') y
ORDER BY cateId, id
下面是SQL Server的写法
查询5个分类,每个分类最多返回5条
分类4实际多余5条,但查询仅返回五条
id name cateId rn
----------- ---- ----------- --------------------
1 A 1 1
2 B 1 2
3 C 2 1
4 D 2 2
5 E 3 1
6 R 3 2
7 G 4 1
8 H 4 2
9 R 4 3
10 GG 4 4
11 HH 4 5
如果不同分类要返回不同的行,下面是分类1,2,3最多返回2条其他最多返回5条
如果是MYSQL,没有ROW_NUMBER,可以参考下面这样实现ROW_NUMBER()OVER(PARTITION BY
没怎么看懂。类似这样
where 条件1 and 条件2 and 条件3 and 条件4 and 条件5 limit 25可以吗不知道你是不是要进行分组,然后取各个分组5个?Here you go