python多维元组如何全部转换成列表

Answer 1

>>> a = ((1,2,3),(4,5,6,),(7,8,9))
>>> print map(list, a)
[[1, 2, 3], [4, 5, 6], [7, 8, 9]]

Answer 2

a = ((1,2,3),(4,5,6,),(7,8,9))
b = list(a)
b[:] = [list(c) for c in b]
print b

Answer 3

任意维度的tuple，稍作修改可以适应任意list, iterable:

def flatten(xs):
    for x in xs:
        if isinstance(x, tuple):
            for xx in flatten(x):
                yield xx
        else:
            yield x


a = ((1,2,3),(4,5,6,),(7,8,9))
print list(flatten(a))

a = ((1, 2, 3),((4, 5), (6)), ((7, 8, 9)))
print list(flatten(a))

Answer 4

也凑个热闹吧 :)

a = ((1, 2, 3), (4, 5, 6), (7, 8, 9))
b = []
for i in range(len(a)):
    b.append(list(a[i]))
print b

Answer 5

有一个非常轻量级也非常经典与方便的python库，叫jerk，只有4个api，对于这种类型转换的问题，用起来非常方便。一楼利用map处理是非常方便与得体的。但是若对于更加复杂或者其他的情况，则不好弄。
如 a = ( (1, 2, 3), 1, 2, 3, (1, (1, 1), set([1, 2])), {1: 'tutorial'} )
对于这类数值类型转换问题，使用jerk中的xlist即可。
(jerk 的四个api分别是：xlist, xtuple, xint, xlen)

    #先来安装jerk库
    $ pip install jerk

    #使用jerk中xlist的范例
    $ python
    >>> from jerk import *
    >>> a = ( (1, 2, 3), 1, 2, 3, (1, (1, 1), set([1, 2])), {1: 'tutorial'} )
    >>> print xlist(a)
    >>> [[1, 2, 3], 1, 2, 3, [1, [1, 1], set([1, 2])], {1: 'tutorial'}]

关于jerk的地址是Tutorial on github.