这段c++ 代码为什么还会重复运行应用程序？

Question

#include <stdio.h>
#include <Windows.h>
#pragma comment( linker, "/subsystem:windows /entry:mainCRTStartup" )


static BOOL mkProc(const char *path, LPSTR cmd) {
    STARTUPINFO info={sizeof(info)};
    PROCESS_INFORMATION processInfo;
    return CreateProcess(path, cmd, NULL, NULL, TRUE, 0, NULL, NULL, &info, &processInfo);
}

static const char *commands[] = {
"C:\\Program Files\\Tencent\\QQ\\QQProtect\\Bin\\QQProtect.exe",
"C:\\Program Files\\Tencent\\QQMusic\\QQMusic.exe",
    NULL
};

BOOL check_exsit(LPSTR test){
 HANDLE m_hMutex = CreateMutex(NULL, FALSE, test); //创建互斥量

// 如果程序已经存在并且正在运行 
if (GetLastError() == ERROR_ALREADY_EXISTS)
{ 
    CloseHandle(m_hMutex); 
    m_hMutex = NULL; 
    return true; 

}
return false;
}


int main(int argc, char **argv) {
    for (int i = 0; commands[i]; ++i) {
        LPSTR cmd = (LPSTR) commands[i];
        if(check_exsit(cmd)){
        //激活已经打开的窗口
    }
    else{ 
         if (!mkProc(NULL, cmd)) {
         fprintf(stderr, "ERROR: cannot spawn %s\n", cmd);

     }
   }
    }
 return 0;
}

Answer 1

HANDLE m_hMutex = CreateMutex(NULL, TRUE, test); //创建互斥量

// 如果程序已经存在并且正在运行 if (GetLastError() == ERRORALREADYEXISTS) {

return true; 

} return false; }