javascript如何删除二维关联数组中的某个元素后返回未被删除的其他数组元素？

Question

var arr2 = new Array();

        arr2["person"] = new Array();
        arr2["person"][0] = "name";
        arr2["person"][1] = "age";
        arr2["person"][2] = "sex";
        arr2.push(arr2["person"]);
        arr2["person2"] = new Array();
        arr2["person2"][0] = "name2";
        arr2["person2"][1] = "age2";
        arr2["person2"][2] = "sex2";
        arr2.push(arr2["person2"]);
        arr2["person3"] = new Array();
        arr2["person3"][0] = "name3";
        arr2["person3"][1] = "age3";
        arr2["person3"][2] = "sex3";
        arr2.push(arr2["person3"]);
        //
        alert(arr2);

// arr2=arr2.pop(arr2["person2"]);

        arr2.pop(arr2["person2"]);
        alert(arr2);
        由于我项目中用到了二维数组，需要对二维数组中的某个元素进行删除，以上是我自己写的一个测试代码，测试出来的结果是无论我删除的是二维数组中的哪个元素，用alert弹出的都是除了最后一个元素的其他数组元素，而没法弹出删除后剩下的那些元素，请大神帮帮我！
        

Answer 1

pop() 方法从数组末尾移除最后一项，然后返回移除的项。

用splice()删除

Answer 2

delete arr2["person3"];
delete arr2["person2"];
delete arr2["person"];

Answer 3

你这结构还真是挺奇怪……

假设你要删除的是person2吧，直接删掉arr2里面的就行了嘛。

arr2 = arr2.some((item,index,arr) => (item === arr['person2'] && delete arr[index] && delete arr['person2']));
console.log(arr2);

简单点，用for也行：

for(let i = 0; i < arr2.length; i++) {
    if(arr2[i] === arr2['person2']) {
        delete arr2['person2'];
        delete arr2[i];
        break;
    }
}