php - 调用API,对方总是说参数放在BODY里面

Question

请问PHP CURL post json参数如何放在body里面

private function getAccessToken(){

        $url='http://114.215.198.210:8081/api_v1/oauth2/accessToken';
        $postData=array('client_id'=>$this->cliendId,'client_secret'=>$this->client_secret,'grant_type'=>'client_credentials');
        echo $postJosnData = json_encode($postData);
        $ch = curl_init($url);
        curl_setopt($ch, CURLOPT_HEADER, 0);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
        curl_setopt($ch, CURLOPT_POST, 1);
        curl_setopt($ch, CURLOPT_POSTFIELDS, $postJosnData);    
        curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);  
        curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE);  
        $data = curl_exec($ch);
        return $data;
    }

没错吧？对方总是说请求参数要放在BODY里面

Answer 1

新增下面这句试试

 curl_setopt($ch, CURLOPT_HTTPHEADER, array(                   
        'Content-Type: application/json',  
        'Content-Length: ' . strlen($postData))           
    ); 

Answer 2

post请求body一般有两种格式，json和form。你用的json，可能对方用的form

Answer 3

php不懂，不过request的时候是可以把数据放到request body里的，看这个

http://stackoverflow.com/ques...