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select uid from user where uid = 70 or uid =68 or uid = 69;
mysql返回的是
686970
如何让mysql返回
706869
这样的结果,就是按照where的条件先后来返回.
业精于勤,荒于嬉;行成于思,毁于随。
SELECT id, name FROM mytable WHERE name IN ('B', 'A', 'D', 'E', 'C') ORDER BY FIELD(name, 'B', 'A', 'D', 'E', 'C')
网上随便找下就有了
select uid from user where uid in( 70 ,68 , 69) order by fine_in_set('uid','70,68,69');
select uid from user where uid = 70 or uid =68 or uid = 69 order by uid desc
select uid from user where uid = 70 or uid =68 or uid = 69 order by uid desc;
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网上随便找下就有了
select uid from user where uid = 70 or uid =68 or uid = 69 order by uid desc;