php微信开发，求大牛看看那里问题

Question

第一个if语句里有语法错误吗？面向对象的就没错，面向对象的就错了
class Wechat_base_api{

public function get_access_token(){
                   require_once('connect.php');
                   $tim=time();
                   $sql="select * from get_access_token where id=0 and updated_time> $tim";
                  $resu= mysql_query($sql);
                  if($resu){
                      $row=mysql_fetch_assoc($resu);
                      $access_token=$row['content'];
                      return $access_token;
                     
                  }else{
                       $url = "https://api.weixin.qq.com/cgi-bin/token?grant_type=client_credential&appid=wx5d4c7d2e8ffd5793&secret=4379ef7213c36eae5dc2ab91f9f6aced";                
                       $access_token_Arr =$this->https_request($url);
                      
                    $access_token= $access_token_Arr['access_token'];
                    $newtime=time()+7200;
                     $sqll="update get_access_token set content='{$access_token}' ,updated_time=$newtime where id=0";
                     mysql_query($sqll);
                       return $access_token_Arr['access_token'];
                     
                    
                  }
            }
}

Answer 1

面向对象的就没错，面向对象的就错了

看不懂你要问什么

Answer 2

看下$resu是什么?
话说你的mysql_query就能这么直接用了?

Answer 3

既然都面向对象了还手动引用数据库