我正在构建一个包含关于树木信息的应用程序。树木属于许多区域。所以为了解决这个问题,我创建了两个数据表,分别叫做Trees和TreeZones,它们有主键和外键相匹配。我使用了"hasMany"和"belongsTo"操作符来建立这两者之间的关系。实际上一切都运行良好,但是有一个问题。该应用程序有REST API控制器。在index函数中,我正在获取所有树木数据。我也需要区域。我像这样解决了这个问题:
/**
public function index()
{
$trees = Tree::all();
foreach($trees as $key => $tree){
$treeData = Tree::find($tree->id);
foreach($treeData->zones as $zone)
{
$trees[$key]['zones'][] = $zone->zone;
}
}
return ['data'=>$trees];
}
输出结果如下:
{
"id": 1,
"name": "Kavak Ağacı",
"min": "-45.6",
"max": "-42.8",
"url": "https://p4.wallpaperbetter.com/wallpaper/255/713/198/poplar-trees-near-lake-wallpaper-preview.jpg",
"zones": [
{
"zone": "2a"
},
{
"zone": "4b"
}
]
},
.
.
.
}
但是我希望结果看起来像这样:
{
"id": 1,
"name": "Kavak Ağacı",
"min": "-45.6",
"max": "-42.8",
"url": "https://p4.wallpaperbetter.com/wallpaper/255/713/198/poplar-trees-near-lake-wallpaper-preview.jpg",
"zones": [
"2a",
"4b",
"5c"
]
},
.
.
.
}
如何用简洁的解决方案解决这个问题?
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你可以使用
transform()方法,并且使用急切加载而不是在foreach循环中使用DB调用。 试试这个public function index() { $trees = Tree::with(['zones'])->get(); $trees->transform(function($tree, $key) { foreach ($tree->zones as $zoneKey => $zone) { $trees["zones"][$zoneKey] = $zone->name //如果你有name列 } return $trees; }) return ['data'=>$trees]; }