主要问题是我可以选择周一到周日,而我想限制周二、周四、周六和周日,只选择周一、周三和周五 这是我尝试过的代码,但我实际上不知道为什么它不起作用:
谢谢!!!!
<form action="insertar_reserva_tarde.php" method="POST">
<label for="fecReserva">Día:</label>
<input type="date" name="fecReserva" id="fecReserva" min="2023-06-15" max="2023-07-15"required>
<br>
<label for="horIniReserva">Hora de inicio:</label>
<select name="horIniReserva" id="horIniReserva">
<option value="17">17:00</option>
<option value="18">18:00</option>
<option value="19">19:00</option>
<option value="20">20:00</option>
</select>
<br>
<label for="horFinReserva">Hora de fin:</label>
<select name="horFinReserva" id="horFinReserva">
<option value="18">18:00</option>
<option value="19">19:00</option>
<option value="20">20:00</option>
<option value="21">21:00</option>
</select>
<br>
<input type="hidden" name="pista" value="1">
<input type="hidden" name="idHorario" value="1">
<input type="submit" value="Reservar">
</form>
<?php
if(isset($_POST['fecReserva'])){
$date = strtotime($_POST['fecReserva']);
$dayOfWeek = date('N', $date); // obtiene el número del día de la semana (1 = lunes, 2 = martes, etc.)
if($dayOfWeek == 1 || $dayOfWeek == 3 || $dayOfWeek == 5){
echo "<p>La fecha seleccionada es el ".date('d/m/Y', $date)."</p>";
} else {
echo "<p>Sólo se permiten reservas en Lunes, Miércoles y Viernes.</p>";
}
}
?>
<script>// Everything except weekend days
const validate = dateString => {
const day = (new Date(dateString)).getDay();
if (day==2 || day==4 || day==6 || day==0 ) {
return false;
}
return true;
}
// Sets the value to '' in case of an invalid date
document.querySelector('input').onchange = evt => {
if (!validate(evt.target.value)) {
evt.target.value = '';
}
}
</script>
目的是仅选择周一、周三和周五
Copyright 2014-2025 https://www.php.cn/ All Rights Reserved | php.cn | 湘ICP备2023035733号
您的问题似乎是您将侦听器附加到输入的更改事件,然后向该事件返回 false。
如果您只想选择奇数天(基于 ECMAScript 天编号),则该函数只需返回
!!(dayNum % 2)的结果。输入类型日期的值是格式为 YYYY-MM-DD 的时间戳,它将被解析为 UTC,因此如果使用
new Date(value)您需要获取 UTC 日期.下面通过一条消息的显示来说明逻辑,故意取消表单提交,从而在不提交的情况下显示成功和失败。
还有许多其他方法可以实现相同的结果,例如您可以使用 valueAsDate 而不是而不是调用 Date 构造函数。您还可以使用允许或不允许的日期数组并对其进行测试,等等。
window.onload = () => { // Related elements let form = document.getElementById('calendar'); let msg = document.getElementById('msg'); // The listener let checkDate = evt => { // Cancel submit if called from submit if (evt.type == 'submit') evt.preventDefault(); // Value parsed as UTC so get UTC day let day = new Date(form.theDate.value).getUTCDay(); // Check if day is valid let isValid = !!(day % 2); // Do stuff based on whether isValid is true or false // Show message based on selected day let days = ['Sunday','Monday','Tuesday','Wednesay','Thursday','Friday','Saturday'] msg.textContent = `Selected day is ${days[day]}, ` + `${isValid? 'pass.' : 'fail. Must be a Monday, Wednesday or Friday'}`; return isValid; } // Attach listeners - deal with form being submitted without setting a date form.addEventListener('change', checkDate); form.addEventListener('submit', checkDate); }#msg { color: #999999; font-family: sans-serif; }