javascript - 正则匹配字符

Question

url = ‘http://1dwen.cn/index.php/joi...’
怎样用正则匹配到uid后面的22这个值，哪位大神可以帮忙看下

Answer 1

'http://1dwen.cn/index.php/uid/22/join/team_list?share_text=3&share_pic=12'.match(/http:\/\/1dwen\.cn\/index\.php\/uid\/(\d+)/)[1]

Answer 2

我是否可以理解为你只需要匹配最后一个数字

\d+(?=[^\d]*$)

Answer 3

/https?:\/\/(?:[^\/]+\/)+(\d+)/

Answer 4

var url = new URL("http://1dwen.cn/index.php/join/team_list/uid/22?share_text=3&share_pic=12");
var pathname = url.pathname;
var reg = /\d+$/gi;
var result = pathname.match(reg);

Answer 5

js 或者 java的话用indexOf和subString之类的方法就可以搞定

 var index = 'asdf'.indexOf('s') ;//  ---> 1
 'asdf'.substring(index); //....

如果是用正则表达式(js版),可以使用正则表达式分组:

t = /uid\/(.*)\?/.exec('http://1dwen.cn/index.php/join/team_list/uid/22?share_text=3&share_pic=12');
console.log(t[1]);