Table of Contents
本文主要和大家分享php判断json格式是否正确的方法,主要以代码的方式和大家分享,希望能帮助到大家。
1、校验json格式是否有误:
人性化的输出json错误!
2、带中文字的数组转json方法一(推荐)
加参数:JSON_UNESCAPED_UNICODE
3、另一种方法将带中文字的数组转json方法:
4、不能有换行、制表符:这个非常坑,经常排除了所有的错误还是出不来,就是这个地方,多了个换行符啥的,尤其是在excel编辑之后再导入到数据库,然后再用php取出的时候!
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PHP method to determine whether json format is correct

Mar 27, 2018 am 11:34 AM
javascript json php


本文主要和大家分享php判断json格式是否正确的方法,主要以代码的方式和大家分享,希望能帮助到大家。

1、校验json格式是否有误:

function data($value) {
    $res = json_decode($value, true);    
    $error = json_last_error();    
    if (!empty($error)) {        echo "<pre class="brush:php;toolbar:false">";
        print_r($value);        echo "
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"; } return $res; }

延伸:json_last_error可以判断返回 JSON 编码解码时最后发生的错误。 错误如下:有对应的数字编码,但是只要非空,就表示有错误,对于一般的json格式校验来说,已经足够了!
PHP method to determine whether json format is correct

0 = JSON_ERROR_NONE No error has occurred

1 = JSON_ERROR_DEPTH The maximum stack depth has been exceeded

2 = JSON_ERROR_STATE_MISMATCH Invalid or malformed JSON

3 = JSON_ERROR_CTRL_CHAR Control character error, possibly incorrectly encoded

4 = JSON_ERROR_SYNTAX Syntax error

5 = JSON_ERROR_UTF8 Malformed UTF-8 characters, possibly incorrectly encoded PHP 5.3.3

人性化的输出json错误!

<?php
     if (!function_exists(&#39;json_last_error_msg&#39;)) {         function json_last_error_msg() {
             static $ERRORS = array(
                 JSON_ERROR_NONE => &#39;No error&#39;,
                 JSON_ERROR_DEPTH => &#39;Maximum stack depth exceeded&#39;,
                 JSON_ERROR_STATE_MISMATCH => &#39;State mismatch (invalid or malformed JSON)&#39;,
                 JSON_ERROR_CTRL_CHAR => &#39;Control character error, possibly incorrectly encoded&#39;,
                 JSON_ERROR_SYNTAX => &#39;Syntax error&#39;,
                 JSON_ERROR_UTF8 => &#39;Malformed UTF-8 characters, possibly incorrectly encoded&#39;
             );             $error = json_last_error();             return isset($ERRORS[$error]) ? $ERRORS[$error] : &#39;Unknown error&#39;;
         }
     }
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2、带中文字的数组转json方法一(推荐)

加参数:JSON_UNESCAPED_UNICODE

$array = array(&#39;key&#39; => &#39;value&#39;, &#39;test&#39; => array(&#39;测试一下&#39;, 2, 3));echo "<pre class="brush:php;toolbar:false">";
print_r(json_encode($array, JSON_UNESCAPED_UNICODE));echo "
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";exit;

PHP method to determine whether json format is correct

3、另一种方法将带中文字的数组转json方法:

//将汉字,特殊字符原样变成json数据function ch_json_encode($data) {
    $ret = ch_urlencode($data);    $ret = json_encode($ret);    return &#39;\&#39;&#39; . addslashes(urldecode($ret)) . &#39;\&#39;&#39;;
}//汉字,特殊字符变可读懂的字符串主程序function ch_urlencode($data) {
    if (is_array($data) || is_object($data)) {        foreach ($data as $k => $v) {            if (is_scalar($v)) {                if (is_array($data)) {                    $data[$k] = urlencode($v);
                } else if (is_object($data)) {                    $data->$k = urlencode($v);
                }
            } else if (is_array($data)) {                $data[$k] = ch_urlencode($v); // 递归调用该函数
            } else if (is_object($data)) {                $data->$k = ch_urlencode($v);
            }
        }
    }    return $data;
}
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php5.2以后自带json_decode函数,但是对json文本串的格式要求非常严格。

很可能使用该函数得到的返回值是NULL,没有返回数组只有可能要么是编码问题,要么就是json返回的数据又特殊字符别无其他原因,下面是解决方法:

可以使用使用json_last_error()函数获取到的返回值来帮助我们判断出问题的原因。

其中如果提示错误JSON_ERROR_SYNTAX(Syntax error),表示json串格式错误。

可以通过以下几个方式排错:

  1. json字符串必须以双引号包含

$output = str_replace("&#39;", &#39;"&#39;, $output);
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  1. json字符串必须是utf8编码

$output = iconv(&#39;gbk&#39;, &#39;utf8&#39;, $output);
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3.不能有多余的逗号 如:[1,2,],用正则替换掉

preg_replace(&#39;/,\s*([\]}])/m&#39;, &#39;$1&#39;, $output)
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4、不能有换行、制表符:这个非常坑,经常排除了所有的错误还是出不来,就是这个地方,多了个换行符啥的,尤其是在excel编辑之后再导入到数据库,然后再用php取出的时候!

$jsonstr = &#39;

{"succ":true,"data":{"id":"31","keywords":"","description":"","jianjie":"       ","jianjie_short":"bb","nav":"ccc","deleted":"0","url":"http:\/\/travel.sina.com.cn\/beijing\/

"}}&#39;;//$ret=preg_replace("/\t/", " ", $ret);  

//$jsonstr = preg_replace("/\n/", &#39; &#39;, $jsonstr);$jsonstr = str_replace("\n", &#39; &#39;, $jsonstr);//print_r($jsonstr);exit;//$jsonstr = str_replace (&#39;\n&#39;,&#39;&#39;, $jsonstr);$jd = json_decode($jsonstr,true);$errorinfo = json_last_error();//print_r(JSON_ERROR_DEPTH);

print_r($jd);
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当对UTF-8编码的文件进行操作时,如果要把读取的内容当作文本内容来处理,最好先对BOM进行一些处理,这个问题在PHP6中得到了解决(可以设置文本/二进制读取模式),有兴趣的朋友可以自己查找PHP6的手册。

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PHP如何判断json格式是否正确

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