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Home Backend Development PHP Tutorial 写了一个简单留言板发布代码,但总是无法把留言录入MySQL数据库中,求大神指点错误!

写了一个简单留言板发布代码,但总是无法把留言录入MySQL数据库中,求大神指点错误!

Jun 23, 2016 pm 02:24 PM

    我初学php和mysql,模仿php100视频教程做一个留言板发布网站,但点击“留言“按钮后总是弹出“留言失败!”,同时数据库中也没有导入信息,求大神看一下哪出代码出问题了,谢谢!
     数据库 名称:test_liuyanban
     表 名称:message
     字段:int(主键)、username(用户名)、email(邮箱)、content(留言内容)。
     一共两个文件:conn.php和index.php
     conn.php:
$conn = @mysql_connect('localhost','root','12345')or die('连接失败!');
@mysql_select_db("test_liuyanban")or die('没有该数据库!');
mysql_query("set names 'GBK'");
?>
     
     index.php:
include_once'conn.php';
if($_POST['post']){
    $sql="insert into `message` (id,username,email,content) values ('','$_POST[username]','$_POST[email]','$_POST[content]')";
    $result=mysql_query($sql);
    if($result){
        echo"<script>alert('留言成功!');location.href='index.php'</script>";
    }else{
        echo"<script>alert('留言失败!');location.href='index.php'</script>";
    }
}
?>




    

        
        
            
            
        
        
            
            
        
        
            
            
        
        
        
        
    




回复讨论(解决方案)

$sql="insert into `message` (id,username,email,content) values ('',$_POST['username'],$_POST['email'],$_POST['content'])";

$sql="insert into `message` (id,username,email,content) values ('',$_POST['username'],$_POST['email'],$_POST['content'])";

按照这个方法试了下,网页无法正常显示,没改前浏览器还能看到这个

$result=mysql_query($sql) or die(mysql_error());  这样有报错没

$result=mysql_query($sql) or die(mysql_error());  这样有报错没
加入了你说的代码,点击“回复”后浏览器显示这个




怎么解决?谢谢指导




$result=mysql_query($sql) or die(mysql_error());  这样有报错没
加入了你说的代码,点击“回复”后浏览器显示这个




怎么解决?谢谢指导





说错了,是点击“留言”

你的表中没有email 字段,show create table message; 看看

你的表中没有email 字段,show create table message; 看看
找到答案了,我犯了个低级错误,把数据库里的字段名“email”打成了“emai”,哈哈

用户名:
E-mail:
留言内容:
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