归纳整理oracle数据库去除重复数据常用的方法

create table nayi224_180824(col_1 varchar2(10), col_2 varchar2(10), col_3 varchar2(10));
insert into nayi224_180824
select 1, 2, 3 from dual union all
select 1, 2, 3 from dual union all
select 5, 2, 3 from dual union all
select 10, 20, 30 from dual ;
commit;
select*from nayi224_180824;

select distinct t1.* from nayi224_180824 t1;

select distinct t1.col_2, col_3 from nayi224_180824 t1

select *
  from (select t1.*,
               row_number() over(partition by t1.col_2, t1.col_3 order by 1) rn
          from nayi224_180824 t1) t1
 where t1.rn = 1
;

select *
  from nayi224_180824 t
 where (t.col_2, t.col_3) in (select t1.col_2, t1.col_3
                                from nayi224_180824 t1
                               group by t1.col_2, t1.col_3
                              having count(1) > 1)

select *
  from (select t1.*,
               count(1) over(partition by t1.col_2, t1.col_3) rn
          from nayi224_180824 t1) t1
 where t1.rn > 1
;

delete from nayi224_180824 t
 where t.rowid in (
                   select rid
                     from (select t1.rowid rid,
                                   count(1) over(partition by t1.col_2, t1.col_3) rn
                              from nayi224_180824 t1) t1
                    where t1.rn > 1);

delete from nayi224_180824 t
 where t.rowid in (select rid
                     from (select t1.rowid rid,
                                  row_number() over(partition by t1.col_2, t1.col_3 order by 1) rn
                             from nayi224_180824 t1) t1
                    where t1.rn > 1);

delete from nayi224_180824 t
 where t.rowid not in
       (select max(rowid) from nayi224_180824 t1 group by t1.col_2, t1.col_3);