使用php://input接收数据流(还有多个参数的解决办法)
最近的工作中接触到一个手机上传图片到服务器的小程序,刚开始一直在想该用怎样的方式去接收数据,最后在网上看到大家都用php://input来接收。就去查了下php://input的官方介绍,确实可以,除了在enctype= multipart/form-data 情况下,是无法接收到流的,其
最近的工作中接触到一个手机上传图片到服务器的小程序,刚开始一直在想该用怎样的方式去接收数据,最后在网上看到大家都用php://input来接收。就去查了下php://input的官方介绍,确实可以,除了在enctype="multipart/form-data"情况下,是无法接收到流的,其他情况下都可以。既然这个可以,我就在本地先写个测试文件
上传文件
//@file phpinput_post.php
$data=file_get_contents('btn.png');
$http_entity_body = $data;
$http_entity_type = 'application/x-www-form-urlencoded';
$http_entity_length = strlen($http_entity_body);
$host = '127.0.0.1';
$port = 80;
$path = '/image.php';
$fp = fsockopen($host, $port, $error_no, $error_desc, 30);
if ($fp) {
fputs($fp, "POST {$path} HTTP/1.1\r\n");
fputs($fp, "Host: {$host}\r\n");
fputs($fp, "Content-Type: {$http_entity_type}\r\n");
fputs($fp, "Content-Length: {$http_entity_length}\r\n");
fputs($fp, "Connection: close\r\n\r\n");
fputs($fp, $http_entity_body . "\r\n\r\n");
while (!feof($fp)) {
$d .= fgets($fp, 4096);
}
fclose($fp);
echo $d;
}
?>
接收文件
/**
*Recieve image data
**/
error_reporting(E_ALL);
function get_contents() {
$xmlstr= file_get_contents("php://input");
$filename=time().'.png';
if(file_put_contents($filename,$xmlstr)){
echo 'success';
}else{
echo 'failed';
}
}
get_contents();
?>
运行test.php你就可以看到相应的结果,成功了,也在相应目录下看到了我刚才上传的文件。如果你做服务端,就只需要接收文件里面的php代码了。我上面模拟的上传就需要根据客户端来相应构造了,我后面也和客户端对接上了。所以是可以用的,还有就是客户端上传的时候可能会一些数据问题,因为我们在这个过程中出现了各种状况。
今天公司要求用APP发送一个图片到PHP程序接收并保存起来,而且中间还需要很多参数!
以前没有做过APP和PHP交互,这次算是一个挑战吧(对一个没有人指导实习生来说)
1.APP发1.jpg,而且带有两个参数一个是假设是X和另外一个假设是Y
2.PHP负责接受X,Y和1.jpg,并且还要保存1.jpg到服务器
步骤:
1.PHP页面代码
$data = file_get_contents(‘php://input’);//这样可以获取到未经处理的原数据(保持发送的图片流不被破坏),在APP上使用X#Y#图片流使用http发送到PHP页面
//然后PHP页面进行数据处理和分割
2.数据处理
先分割数据流
$vars = explode(“#”,$data,3);//这样防止对图片流造成破坏只分割成三份即可
/*省去若干代码*/
$img = $vars[2];
$path = ‘/var/www/uploads/’;
$newfilename = time().”.jpg”;
$file = $path.$newfilename;
$handle = fopen($file, “w”);
if ($handle) {fwrite($handle,$img);
fclose($handle);
}
^_^,看看/var/www/目录下是不是生成了一个图片?

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