Usage of listagg function in oracle
The LISTAGG function concatenates a set of rows of data into a string, using the specified concatenation character to separate elements. Usage includes: 1. Join all values in a column; 2. Separate values using join characters; 3. Ignore NULL values; 4. Partition by group; 5. Join values sequentially.
Usage of LISTAGG function in Oracle
Definition:
The LISTAGG function will A set of rows of data are concatenated into a string, with the individual elements separated using the specified concatenation character.
Syntax:
<code>LISTAGG(expression, delimiter [IGNORE NULLS]) OVER (PARTITION BY partition_expression ORDER BY order_expression)</code>
Parameters:
- expression: the data column to be connected
- delimiter: Character delimiter between connection elements (optional)
- IGNORE NULLS: Ignore NULL values (optional)
- partition_expression: Partitioned data column, specifying where the component elements are located Group of (optional)
- order_expression: Specifies the order in which elements are connected (optional)
Usage:
The LISTAGG function is usually used Used to combine multiple lines into a single string for easier display or processing. The following is its typical usage:
1. Concatenate all values in a column
<code>SELECT LISTAGG(name) FROM table_name;</code>
2. Separate values using joiners
<code>SELECT LISTAGG(name, ', ') FROM table_name;</code>
3. Ignore NULL values
<code>SELECT LISTAGG(name IGNORE NULLS) FROM table_name;</code>
4. Partition by group
<code>SELECT LISTAGG(name) OVER (PARTITION BY group_id) FROM table_name;</code>
5. Concatenate values in order
<code>SELECT LISTAGG(name) OVER (ORDER BY name) FROM table_name;</code>
Example:
The following table shows an example of using the LISTAGG function to join employee names in the employees table:
Employee ID | Name |
---|---|
1 | John |
2 | Jane |
3 | David |
Use the LISTAGG function to connect all employees Name:
<code>SELECT LISTAGG(name) FROM employees;</code>
Result:
<code>John, Jane, David</code>
Use comma as connector:
<code>SELECT LISTAGG(name, ', ') FROM employees;</code>
Result:
<code>John, Jane, David</code>
Partition by department and join the employees of each department Name:
<code>SELECT LISTAGG(name) OVER (PARTITION BY department) FROM employees;</code>
Result:
<code>John Jane David</code>
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