golang function slice passed as parameter
Function slices in Go language can be passed as parameters to enhance code flexibility. The syntax is as follows: func function(fn func([]int) []int, slice []int) []int, where function receives function slice fn and slice slice as parameters.
Passing function slices as parameters in Go language
In Go language, functions can be passed as parameters to other functions. This is a powerful technique that makes your code more flexible and reusable.
Syntax
The syntax for passing function slices as parameters is as follows:
func function(fn func([]int) []int, slice []int) []int
function
is the receiving function slice Functions with fn
and sliceslice
as parameters. func
defines the type of function slice, which receives an integer slice of length N
and returns an integer slice of length M
.
Practical Case
Let’s look at a practical case of passing function slices as parameters. Suppose we have a function apply
that takes a function slice and a slice and applies each function in the function slice to each element in the slice.
package main import "fmt" func main() { // 定义函数切片 fns := []func(int) int{ func(i int) int { return i + 1 }, func(i int) int { return i * 2 }, } // 定义切片 slice := []int{1, 2, 3} // 将函数切片和切片传递给 apply 函数 result := apply(fns, slice) // 打印结果 fmt.Println(result) } // apply 函数接收一个函数切片和一个切片,并对切片中的每个元素应用函数切片中的每个函数 func apply(fns []func(int) int, slice []int) []int { result := make([]int, len(slice)) for i, v := range slice { for _, fn := range fns { result[i] = fn(v) } } return result }
Output
[]int{2, 4, 6}
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