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Home Backend Development Golang Golang - Returned JSON top-level fields are mutable. How to use it in a structure

Golang - Returned JSON top-level fields are mutable. How to use it in a structure

Feb 06, 2024 am 10:45 AM

Golang - 返回的 JSON 顶级字段是可变的。如何在结构体中使用

问题内容

我有一个来自 API 的 JSON 响应,如下所示:

{
    "1091500": {
      "data": {
        "price_overview": {
          "final_formatted": "$59.99"
        }
      } 
    }
}
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当我解组并访问我需要的价格值时,我的结构工作正常。 price.AppID.Data.PriceOverview.FinalFormatted

此处的结构:

type SteamApp struct {
    AppID struct {
        Data struct {
            PriceOverview struct {
                FinalFormatted string `json:"final_formatted"`
            } `json:"price_overview"`
        } `json:"data"`
    } `json:"1091500"`
}
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我正在尝试解决的是顶级密钥“1091500”。这是由单独函数生成的值,实际上是获取上述数据所需的搜索词。话虽这么说,它是动态的,并且是在运行时通过单独的 API 调用发现的。因为您需要结构中的 JSON 标记,所以我正在努力想出一种方法来概括它。

到目前为止,最好的方法是找到一个以不同方式返回数据的不同 API,但我还没有找到。我还考虑过找到一种方法来“跳过”初始部分,因为我有正确的数据,这只是“阅读”它的问题。预先感谢您,我希望我能很好地解释自己。


正确答案


分两步解组。首先进入映射,然后进入结构类型。您可以通过实现 json.Unmarshaler 自动执行此操作:

package main

import (
    "encoding/json"
    "fmt"
)

var j = []byte(`{
    "1091500": {
      "data": {
        "price_overview": {
          "final_formatted": "$59.99"
        }
      }
    }
}`)

func main() {
    var t T
    err := json.Unmarshal(j, &t)

    fmt.Println(err)
    fmt.Printf("%+v\n", t)
}

type T struct {
    AppID         string `json:"-"`
    PriceOverview struct {
        FileFormatted string `json:"final_formatted"`
    } `json:"price_overview"`
}

func (t *T) UnmarshalJSON(b []byte) error {
    var m map[string]struct {
        Data json.RawMessage
    }

    err := json.Unmarshal(b, &m)
    if err != nil {
        return err
    }

    type T_ T // prevent recursion
    var t_ T_

    for appID, x := range m {
        err := json.Unmarshal(x.Data, &t_)
        if err != nil {
            return err
        }

        *t = T(t_)
        t.AppID = appID

        break
    }

    return nil
}
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在操场上尝试一下:https://www.php.cn/link/8571ddcc1c64ca1fa11891d899cab05d

我假设数据属性只是噪音并使其透明。如果我弄错了,请使用 map[string]json.RawMessage 并将数据字段添加到类型 T。

如果您也想自动编组为相同的格式,请实现 json.Marshaler还有:

func (t T) MarshalJSON() ([]byte, error) {
    type T_ T // prevent recursion

    m := map[string]struct {
        Data T_ `json:"data"`
    }{
        t.AppID: {Data: T_(t)},
    }

    return json.Marshal(m)
}
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