Convert 00:33 to duration in golang
I have a string "12:34" in the format "mm:ss" and I want to convert it to time. duration. Too much time has been wasted on this. What am I doing wrong in this code:
package main import ( "fmt" "strings" "time" ) func parseDuration(input string) (time.Duration, error) { var layout string if strings.Count(input, ":") == 1 { layout = "04:05" } else { layout = "15:04:05" } t, err := time.Parse(layout, input) if err != nil { return 0, err } return t.Sub(time.Time{}), nil } func main() { input := "00:04" duration, err := parseDuration(input) if err != nil { fmt.Println(err) return } fmt.Println(int(duration.Seconds())) // I should get 4 but I get -31622396 }
https://go.dev/play/p/a-ehc-eptrd
Correct answer
The zero value of time type is 1 year 1 month 1st 00:00:00.000000000 utc.
func parseduration(input string) (time.duration, error) { var layout string if strings.count(input, ":") == 1 { layout = "04:05" } else { layout = "15:04:05" } t, err := time.parse(layout, input) if err != nil { return 0, err } return t } fmt.println(time.time{}) // this prints 0001-01-01 00:00:00 +0000 utc fmt.println(parseduration("00:04")) // this prints 0000-01-01 00:00:04 +0000 utc
In your case, you should define a start
object instead of using time.time{}
directly. For example,
package main import ( "fmt" "strings" "time" ) var origin = time.Date(0, 1, 1, 0, 0, 0, 0, time.UTC) func parseDuration(input string) (time.Duration, error) { var layout string if strings.Count(input, ":") == 1 { layout = "04:05" } else { layout = "15:04:05" } t, err := time.Parse(layout, input) if err != nil { return 0, err } return t.Sub(origin), nil } func main() { input := "00:04" duration, err := parseDuration(input) if err != nil { fmt.Println(err) return } fmt.Println(duration.String()) // this prints 4s }
https://www.php.cn/link/bdf0f5f84843f08f00912ae5292162f6
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