Table of Contents
usage instructions
algorithm
Example
Output
in conclusion
Home Backend Development C++ Print nodes in a directed graph that do not belong to any cycle

Print nodes in a directed graph that do not belong to any cycle

Sep 13, 2023 pm 10:25 PM

Print nodes in a directed graph that do not belong to any cycle

In coordination diagrams, identifying hubs that do not belong to any cycle is crucial for different applications. These centers form the basis of acyclic subgraphs and play an important role in understanding the general graph structure. By using efficient graph intersection calculations, such as Profundity First Hunt (DFS) or Tarjan's calculation of closely related parts, we can effortlessly decide and print hubs that do not participate in any loops. These methods ensure the characterization of centers without circular collaboration, provide important knowledge for the non-circular parts of diagrams, and support different critical thinking situations related to diagrams.

usage instructions

  • Depth-first search (DFS) with loop detection

  • Tarjan’s strongly connected component algorithm

Depth-first search (DFS) with loop detection

In this approach, we use depth-first tracking (DFS) to navigate the coordination chart and distinguish cycles on the way. We mark visited centers and keep a list so that centers can be tracked in an ongoing DFS manner. If we hit a trailing edge (reaching the edge of the hub in a sustained DFS manner), we differentiate a cycle. At the end of DFS, the center in the ongoing DFS way will be important for a cycle. Hubs that do not use persistent DFS are not part of any loop and can be printed.

algorithm

  • Perform a Deep First Hunt (DFS) from each unvisited center on the chart.

  • During DFS, visited hubs are marked and added to the ongoing DFS path list.

  • If we encounter a trailing edge (an edge to a hub in the current DFS mode), we distinguish a cycle and mark all hubs in the current DFS mode as part of the cycle.

  • When DFS for a hub is complete, remove it from the list of in-progress DFS paths.

  • After completing the DFS of all hubs, the hubs that do not belong to any cycle will remain unchanged and we can print them.

Example

#include <iostream>
#include <vector>

class Graph {
public:
   Graph(int numVertices);
   void addEdge(int src, int dest);
   void DFS();
private:
   void DFSUtil(int v, std::vector<bool>& visited, std::vector<int>& dfsPath);
   int numVertices;
   std::vector<std::vector<int>> adjList;
};

Graph::Graph(int numVertices) : numVertices(numVertices) {
   adjList.resize(numVertices);
}

void Graph::addEdge(int src, int dest) {
   adjList[src].push_back(dest);
}

void Graph::DFSUtil(int v, std::vector<bool>& visited, std::vector<int>& dfsPath) {
   visited[v] = true;
   dfsPath.push_back(v);

   for (int neighbor : adjList[v]) {
      if (!visited[neighbor]) {
         DFSUtil(neighbor, visited, dfsPath);
      }
      else {
         std::cout << "Cycle found: ";
         for (size_t i = 0; i < dfsPath.size(); ++i) {
            if (dfsPath[i] == neighbor) {
               while (i < dfsPath.size()) {
                  std::cout << dfsPath[i] << " ";
                  ++i;
               }
               break;
            }
         }
         std::cout << std::endl;
      }
   }

   dfsPath.pop_back();
}

void Graph::DFS() {
   std::vector<bool> visited(numVertices, false);
   std::vector<int> dfsPath;

   for (int i = 0; i < numVertices; ++i) {
      if (!visited[i]) {
         DFSUtil(i, visited, dfsPath);
      }
   }
}

int main() {
   Graph graph(6);
   graph.addEdge(0, 1);
   graph.addEdge(1, 2);
   graph.addEdge(2, 3);
   graph.addEdge(3, 4);
   graph.addEdge(4, 1);
   graph.addEdge(4, 5);
   
   std::cout << "DFS traversal with cycle detection:\n";
   graph.DFS();

   return 0;
}
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Output

DFS traversal with cycle detection:
Cycle found: 1 2 3 4 
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Tarjan’s strongly connected component algorithm

Tarjan's calculation is a powerful calculation used to track all key related parts of the coordination diagram. Explicitly related parts are subsets of hubs for which coordination exists between any two hubs in the subset. A hub that is not part of any closely related component is not part of any cycle. By finding key associated parts we can identify hubs that do not belong to any cycle and print them\

algorithm

  • Apply Tarjan's calculations to the bootstrapping diagram to track all key relevant parts.

  • After tracing all the important related parts, distinguish the centers that are crucial for the closely related parts.

  • Hubs that do not belong to any explicitly associated parts do not belong to any loop and can be printed.

  • Both methods do differentiate and print centers that do not belong to any cycle in the coordination chart. The DFS method provides a simpler and more straightforward implementation, while Tarjan's calculations are more complex but provide additional data on focused correlation parts, which can be helpful for specific chart-related tasks. The decision on approach depends on the specific needs and the context of the main pressing issues.

Example

#include <iostream>
#include <vector>
#include <stack>
#include <algorithm>
using namespace std;

class Graph {
   int V;
   vector<vector<int>> adj;
   vector<bool> visited;
   vector<int> disc, low;
   stack<int> st;
   vector<vector<int>> SCCs;
   vector<bool> essentialNodes;

public:
   Graph(int V) : V(V) {
      adj.resize(V);
      visited.resize(V, false);
      disc.resize(V, -1);
      low.resize(V, -1);
      essentialNodes.resize(V, true);
   }

   void addEdge(int u, int v) {
      adj[u].push_back(v);
   }

   void tarjanDFS(int u) {
      static int time = 0;
      disc[u] = low[u] = ++time;
      st.push(u);
      visited[u] = true;

      for (int v : adj[u]) {
         if (disc[v] == -1) {
            tarjanDFS(v);
            low[u] = min(low[u], low[v]);
         } else if (visited[v]) {
            low[u] = min(low[u], disc[v]);
         }
      }

      if (low[u] == disc[u]) {
         vector<int> SCC;
         int v;
         do {
            v = st.top();
            st.pop();
            SCC.push_back(v);
            visited[v] = false;
         } while (v != u);

         SCCs.push_back(SCC);
      }
   }

   void tarjan() {
      for (int i = 0; i < V; ++i) {
         if (disc[i] == -1) {
            tarjanDFS(i);
         }
      }
   }

   void identifyEssentialNodes() {
      for (const vector<int>& SCC : SCCs) {
         for (int v : SCC) {
            for (int u : adj[v]) {
               if (find(SCC.begin(), SCC.end(), u) == SCC.end()) {
                  essentialNodes[u] = false;
               }
            }
         }
      }
   }

   void printEssentialNodes() {
      cout << "Essential Nodes for Each SCC:\n";
      for (int i = 0; i < V; ++i) {
         if (essentialNodes[i]) {
            cout << i << " ";
         }
      }
      cout << endl;
   }
};

int main() {
   Graph g(6);
   g.addEdge(0, 1);
   g.addEdge(1, 2);
   g.addEdge(2, 0);
   g.addEdge(1, 3);
   g.addEdge(3, 4);
   g.addEdge(4, 5);
   g.addEdge(5, 3);

   g.tarjan();
   g.identifyEssentialNodes();
   g.printEssentialNodes();

   return 0;
}
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Output

Essential Nodes for Each SCC:
0 1 2 4 5
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in conclusion

These two methods do solve the problem of identifying centers that do not belong to any cycle in the coordination chart. The DFS method is easy to implement and does not require many additional information structures. Tarjan's calculations, on the other hand, provide additional data on key correlation components, which may be helpful in certain situations.

The decision between the two methods depends on the specific prerequisites of the problem and the requirements for additional data passing through period-independent differentiation centers. In general, if the only goal is to find hubs that do not belong to any cycle, the DFS approach may be favored for its simplicity. Nonetheless, Tarjan's calculations may be an important tool if further examination of key relevant parts is required. Both methods provide proficient arrangements and can be adapted to the properties of the coordination chart and the desired outcome of the exam

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