Table of Contents
Overview
grammar
algorithm
Example
Output
in conclusion
Home Web Front-end JS Tutorial How to check if a browser supports a CSS property using JavaScript?

How to check if a browser supports a CSS property using JavaScript?

Aug 27, 2023 pm 11:09 PM

Overview

In today’s world, there are various browsers available on the system. Therefore, sometimes some Cascading Style Sheets (C.S.S.) properties don't work on this browser. So, to check which CSS properties are supported by a particular browser, JavaScript has a built-in method CSS.supports() which checks whether the browser supports that particular property. The supports() method is supported in all browsers: Opera, Edge, Chrome, and Firefox.

grammar

CSS.supports() method takes key-value pairs as input, which are in string format. The basic syntax used is -

CSS.supports(“propertyName:value”);
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  • supports() - This is a method of the CSS object that checks whether the browser supports the property passed in the supports parameter.

  • propertyName - This contains the name of the CSS property such as display, position, margin, padding, z-index, text alignment, etc.

  • value - It takes the value of a specific property, such as flex, absolute, relative, 20 px, left, right, etc.

So, to learn more about CSS.Supports() method, we will learn through some examples.

Method 1 - In this example, we will pass the CSS style key value directly as a parameter to the CSS.supports() method, which will then determine whether the given CSS property is available for the browser server support.

algorithm

  • Step 1 - Use the supports() method that exists within the CSS object as CSS.supports().

  • Step 2 - Pass any Cascading Style Sheets (CSS) properties as parameters.

  • Step 3 - Use console.log() to print the CSS.supports() method in the console.

  • Step 4 - If true is returned when passing an attribute, then that particular attribute is supported, otherwise the browser does not support it.

Example

<!DOCTYPE html>
<html lang="en">
<head>
   <title>Check CSS property exist in browser using js</title>
</head>
   <body>
      <h1>Open console to see result by pressing (ctrl + shift + i) or F12 on keyboard</h1>
      
      <script>
         console.log(CSS.supports("float:top"));
         console.log(CSS.supports("float:right"));
         console.log(CSS.supports("float:bottom"));
         console.log(CSS.supports("float:left"));
      </script>
   </body>
</html>
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Output

The output of the above code is shown in the figure below. Since the "float:top" and "float:bottom" properties are invalid, they will return false in the console, while the "float:right" and "float:left" properties will return false if they are valid and supported by the browser. true.

如何使用 JavaScript 检查浏览器是否支持 CSS 属性?

Method 2 - In this method we will build a user interface where users can enter CSS properties in given fields and can check if their browser or browsers support these CSS Attributes. no.

algorithm

  • Step 1 - Create a two search box, one for keys and one for values ​​since CSS properties are in key-value form. Assign their specific IDs as "propertyName" and "pval" respectively. Create another output field and an HTML button.

  • Step 2 - Create a function called checkCss() in JavaScript. Arrow functions will be used.

  • Step 3 - Access the two input boxes and store them in variables, concatenate the values ​​of these boxes into the variables.

  • Step 4 - Pass this concatenation variable in CSS.supports() and check the if-else condition.

  • Step 5 - If true is returned, the CSS property is supported, otherwise false is returned, the property is not supported.

Example

<!DOCTYPE html>
<html lang="en">
<head>
   <title>Check CSS property exist in browser using js</title>
   <style>
      body{
         min-height: 90vh;
         display: flex;
         place-content: center;
         flex-direction: column;
         text-align: center;
         background-color: #0a0a0a;
         color: white;
      }
      input{
         width:13rem;
         margin: 5px auto;
         padding: 0.3rem;
         outline: none;
      }
      button{
         width: 5rem;
         margin: 0 auto;
         padding: 0.2rem;
         cursor: pointer;
         background-color: transparent;
         box-shadow: 0 0 5px white;
         border-radius: 5px;
         color: white;
         border: none;
      }
   </style>
</head>
   <body>
      
      <h1>CSS Property Validator</h1>
      <div id="output" style="width:5rem;margin: 5px auto;padding: 0.2rem;"></div>
      <input type="text" id="propertyName" placeholder="Enter propertyName*">
      <input type="text" id="pval" placeholder="Enter value*">
      <button onclick="checkCss()">Check</button>
      
      <script>
         checkCss = () => {
            var p = document.getElementById("propertyName").value;
            var v = document.getElementById("pval").value;
            var pv = p + ":" + v;
            if(CSS.supports(pv)){
               document.getElementById("output").innerText=CSS.supports(pv);
               document.getElementById("output").style.background="green";
               document.getElementById("output").style.color="white";
            } else {
               document.getElementById("output").innerText=CSS.supports(pv);
               document.getElementById("output").style.background="tomato";
               document.getElementById("output").style.color="white";
            }   
         }
      </script>
   </body>
</html>
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Output

The output of the above code is as shown in the figure below. Users can type CSS properties in the given input box and check whether your browser supports these properties. As shown in the figure below, the "display:block" attribute is supported by the browser. and is valid, it returns true.

如何使用 JavaScript 检查浏览器是否支持 CSS 属性?

The output is as shown in the figure below. False is returned, so the attributes filled in the input box are invalid and are not supported by the browser.

如何使用 JavaScript 检查浏览器是否支持 CSS 属性?

in conclusion

The return type of the

supports() method is Boolean because it returns true or false depending on whether the current browser supports the CSS property. The Example 2 interface is particularly useful for developers because it eliminates the need to repeatedly check the console; simply enter your CSS property name and value into the input fields and you will be informed whether the current browser supports it.

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